How getfilename works in c++

Question

1.00/5 (2 votes)

See more:

I want to know how getfilename works.

If I give "image.jpeg" as the input for getfilename what should I expect as output.

Will this method open the file in binary mode?

If I give a file name without extension what output should I expect.

Can anyone suggest any article or explanation of this?

is there any method to read the file-type of a given file??/

Posted 12-May-13 20:58pm

P Uday kishore

Updated 18-Jun-13 21:44pm

v4

Add a Solution

2 solutions

Solution 1

Since you tagged your question (also) with MFC, I am assuming you are asking about CFile::GetFileName[^]. Such method, as the documentation states, returns the name of the file associated to the CFile object.

[Update]
GetFileName does NOT provide the info you are requiring. You may use the extension of the file for guessing its type or (in jpeg case) check the magic number in the header of the file (see "C# How can I test a file is a jpeg?"[^] at Stack Overflow.
[/Update]

Posted 12-May-13 21:15pm

CPallini

Updated 12-May-13 21:28pm

v2

Comments

P Uday kishore 13-May-13 3:19am

That's OK.but what returns am asking filename.jpg in this it returns filename it means????

i need info about filetype reading...

MuraliChagarlamudi 13-May-13 9:03am

I have solution for this,
1st get what is the file extension of a file
For eg if you get a extension of .doc then
if(//file extension is .doc)
{
//enter your code
}
if else(//file extension is .png)
{
//enter your code
}

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Richard MacCutchan · Accepted Answer · 2013-06-18T23:24:00

Solution 2

Look at the documentation. It clearly states that this function returns the name of the file as a string. That is all it does, and it makes no difference what the file type is.

Posted 18-Jun-13 23:24pm

Richard MacCutchan