Get only Host name from the Url

Question

1.00/5 (1 vote)

See more:

Hi I have a urlfor example as below

ex:

VB

http://g-ecx.images-amazon.com
http://z-ecx.images-amazon.com
http://ecx.images-amazon.com
http://completion.amazon.com
http://client-log.amazon.com
http://www.amazon.com/184-8984226-0489751
http://www.amazon.com/access
http://www.amazon.com/gp/product/B0083PWAPW/ref=kin_dev_gw_dual_t/184-8984226-04...
http://www.amazon.com/gp/product/B007OZNZG0/ref=kin_dev_gw_dual_c/184-8984226-04...
http://www.amazon.com/gp/prime/signup/videos/ref=nav_menu_video_redirect_combine...
http://www.amazon.com/gp/prime/signup/videos/ref=nav_menu_video_pic_redirect_com...
http://www.amazon.com/gp/prime/signup/videos/ref=nav_menu_shipping_redirect_comb...
http://www.amazon.com/gp/prime/signup/videos/ref=nav_menu_shipping_pic_redirect_...

Now i want to retrieve only Domain name i.e amazon out of these urls.Can any one did this before??

Thanks,
Prasant

Posted 19-Mar-13 18:45pm

User CP

Add a Solution

Comments

Deependra Khangarot 20-Mar-13 0:58am

Hi Prasant,

Can you provide the project type, Web or windows.

User CP 20-Mar-13 1:18am

HI Deep,Its a web project type

Sergey Alexandrovich Kryukov 20-Mar-13 1:20am

I'm just curious: do you think is someone did not do it before, this person should not be trusted in solution of this super sophisticated problem? :-)
And why do you thing that Amazon is a host name?
—SA

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Deependra Khangarot · Answer 1 · 2013-03-19T19:05:00

Solution 1

C#

var uri = new Uri("http://www.amazon.com/184-8984226-0489751");
string[] splitHostName = uri.Host.Split('.');
if (splitHostName.Length >= 2)
    {
       string HostName = splitHostName[splitHostName.Length - 2];
    }

Posted 19-Mar-13 19:05pm

Deependra Khangarot