Jquery code not working in any browser

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Jquery code is not properly worked in any browser. The faidin() faidout() hide() show() fuctions are not properly worked in the any browser.. please help me what i should do??

Posted 4-Mar-13 18:30pm

Sandeep90409

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Matej Hlatky 5-Mar-13 2:08am

There is no faidin() nor faidout() function in jQuery.

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Sergey Alexandrovich Kryukov · Answer 1 · 2013-03-04T18:41:00

Solution 1

They do work. You just fail to use them correctly. As you did not provide any code, that's all anyone can tell you about it.

Good luck,

—SA

Posted 4-Mar-13 18:41pm

Sergey Alexandrovich Kryukov

vinodkumarnie · Answer 2 · 2013-03-05T19:49:00

JQuery works nicely in all browsers. And it is case sensitive. First know basics and try with examples. I think you are not serious in asking Questions..

Refer below links for some JQuery examples..

http://api.jquery.com/show/[^]
http://api.jquery.com/hide/[^]
http://api.jquery.com/fadeIn/[^]
http://api.jquery.com/fadeOut/[^]