why i get error when put dynamic variable

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class Base
   {
       int BAx;
       int BAy;
       public Base(int _x, int _y)
       {
           BAx = _x;
           BAy = _y;
       }
   }
   class Child : Base
   {
       int CHx;
       int CHy;
       public Child(int _x, int _y)
           : base(0, 1) // i do not get Error when the argument passed in base constructor is static, but if i change argument to dynamic like this 
//public Child(int _x, int _y) : base(int D,int E) i get compilation error
       {
           CHx = _x;
           CHy = _y;
       }
   }
   class Program
   {
       static void Main(string[] args)
       {
       }
   }

Posted 26-Feb-13 12:51pm

Anderso0on

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Sergey Alexandrovich Kryukov 26-Feb-13 19:02pm

What dynamic variable, what error, for goodness sake?
What do you mean "dynamic"?
—SA

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Sergey Alexandrovich Kryukov · Accepted Answer · 2013-02-26T13:10:00

Solution 1

Method argument cannot be "static" in principle. The term "static" does not mean "not dynamic" it means "not instance" for members and "having no instance members" for a type. You have nothing static in your code (except static Main) which is irrelevant. The question as is makes no sense at all.

If you have compilation error with the line public Child(int _x, int _y) : base(int D,int E), this is only because D and E are not declared. Of course, how else? There is nothing about "static" or "dynamic" here; and your understanding of these terms is totally incorrect. Please see also my comment to the question.

For some basic education on this simple matter, please see these discussions:
What makes static methods accessible?[^],
C# windows base this key word related and its uses in the application[^].

—SA

Posted 26-Feb-13 13:10pm

Sergey Alexandrovich Kryukov

Comments

Anderso0on 26-Feb-13 19:22pm

i mean dynamic , static (Variable value) & (constant value)

Sergey Alexandrovich Kryukov 26-Feb-13 19:27pm

I mean nothing! I already explained everything. If you still have a problem with compilation, go use "Improve question" and provide some code which does not compile.
—SA

Sergey Alexandrovich Kryukov 26-Feb-13 19:33pm

Please understand what I'm going to say right. I looked through few of your most recent questions and see just one pattern: it looks you never learn any lessons from answers. Not only you never accept good answers, it even makes the impression that you don't read them or don't understand. Please forgive me if I'm wrong in something, but it makes it hard to make a decision to help you. What's wrong? Do you really fail to understand, or what?
—SA

Anderso0on 26-Feb-13 19:28pm

ok , thank you

Anderso0on 26-Feb-13 19:40pm

really i do not understand what is problem in my code if i write this statment
public Child(int _x, int _y) : base(int D,int E)
and i dont understand your explanation :( :(

Sergey Alexandrovich Kryukov 26-Feb-13 19:45pm

Ah, you see: base(...) is a actually a call of a method (base constructor), you cannot declare variable inside the parameter list, so D and E are not defined.
You can only do:
public Child(int _x, int _y) : base(_x, _y) { /* ... */ }

base call should be used as if it was in the context of { ... } (method body).

More clear now?
—SA

Anderso0on 26-Feb-13 19:48pm

yaeh this is very clear now :)
, but what is problem when i declared new variable in base

Sergey Alexandrovich Kryukov 26-Feb-13 20:10pm

This is not the definition, this is a call. How possibly would you ever define parameters in a call?! Parameters are defined by a callable construct, not at the call.
Is it clear?
If it is, I think you can finally accept my answer (green button)...
—SA

Anderso0on 27-Feb-13 6:55am

thanks alot :)

Sergey Alexandrovich Kryukov 27-Feb-13 10:49am

Great. Always a pleasure to help.
Good luck, call again.
—SA