Onmouseover not working with php

Question

2.00/5 (1 vote)

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Hi all,
i am try to do a mouseover event in php but unable to this.
This the code working fine..

HTML

<div id="main-icon">
<div class="main-icon-left">
 <a href="../index.php"><img src="pb-images/icon-right.png" width="49" height="47" border="0" name="icon right"  alt="icon right" title="icon right" onMouseOver="this.src = 'pb-images/icon-right-hr.png';"  önMouseOut="this.src = 'pb-images/icon-right.png';"></a>
</div>
<div class="main-icon-right"> <a href="machines/binding.php"><img src="pb-images/icon-left.png" width="49" height="47" border="0" name="icon right"  alt="icon right" title="icon right" onMouseOver="this.src = 'pb-images/icon-left-hr.png';"  önMouseOut="this.src = 'pb-images/icon-left.png';"></a></div>
</div>

But using this code in php

PHP

<div id='main-icon'>
<div class='main-icon-left'>
 <a href='../index.php'><img src='pb-images/icon-right.png' width='49' height='47' border='0' name='icon right'  alt='icon right' title='icon right' onMouseOver='this.src = 'pb-images/icon-right-hr.png';'  önMouseOut='this.src = 'pb-images/icon-right.png';'></a>
</div>
<div class='main-icon-right'> <a href='machines/binding.php'><img src='pb-images/icon-left.png' width='49' height='47' border='0' name='icon right'  alt='icon right' title='icon right' onMouseOver='this.src = 'pb-images/icon-left-hr.png';'  önMouseOut='this.src = 'pb-images/icon-left.png';'></a></div>
</div>";

In this the onmouseOver and onmouseOut not working..
If anybody have any idea related to this then please Let me know ASAP

thanks

Posted 18-Nov-12 20:09pm

Rajeshkrathor

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2 solutions

Solution 1

Check your colon an semicolon in mouse out event handler declaration. You can even see it here on CPwhat is wrong :)

Posted 18-Nov-12 20:22pm

n.podbielski

Comments

[no name] 19-Nov-12 2:30am

thanks
I did not get you?
i have put all there is no error coming but event not firing.

Can you send the code what you want to say.

n.podbielski 19-Nov-12 3:25am

Look closely to your second code snippet. Is entire code for handle in handler placeholder? HINT: is in BLUE as html attribute should be? Or it is ending at some point and it is RED?

And I really suggest you to use web browser console to chceck for errors like this. It will save you tons of time.

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Rajeshkrathor · Accepted Answer · 2012-11-19T00:12:00

Solution 2

Hi all,
i found the ans just change the code with this

PHP

<img src="../../pb-images/icon-left.png" width="49" height="47" border="0" name="icon right" alt="icon right" title="icon right" onmouseover="\"this.src" this.src="../../pb-images/icon-left.png" hold=" /><br mode="></img>

Posted 19-Nov-12 0:12am

Rajeshkrathor