How to Fix dropdown value comes from the database

Question

1.00/5 (1 vote)

See more:

How to Fix dropdown value comes from the database and all the dropdwon should have diffeent values there are 6 dropdowns..?
iwant fix the dropdown value aal values are fixed different different..

Posted 21-Oct-12 19:37pm

Niravvasoya

Add a Solution

Comments

Sumit_Kumar_Sinha 22-Oct-12 2:08am

can explain scenario of dropdown.................

Niravvasoya 23-Oct-12 6:08am

this is .aspx file
------------------------

<table border="1">
<tr>
<td colspan="3">

</td>
</tr>
<tr>
<td>
<asp:DropDownList ID="DropDownList1" runat="server" DataTextField="Sub_Name" DataValueField="Sub_Id">

</td>
<td>
:
</td>
<td>
<asp:TextBox ID="txt_Marks1" Width="50px" runat="server" onkeypress="return isNumberKey(event)">
</td>
</tr>
<tr>
<td>
<asp:DropDownList ID="DropDownList2" runat="server" DataTextField="Sub_Name" DataValueField="Sub_Id">

</td>
<td>
:
</td>
<td>
<asp:TextBox ID="txt_Marks2" Width="50px" runat="server" onkeypress="return isNumberKey(event)">
</td>
</tr>
<tr>
<td>
<asp:DropDownList ID="DropDownList3" runat="server" DataTextField="Sub_Name" DataValueField="Sub_Id">

</td>
<td>
:
</td>
<td>
<asp:TextBox ID="txt_Marks3" runat="server" Width="50px" onkeypress="return isNumberKey(event)">
</td>
</tr>
<tr>
<td>
<asp:DropDownList ID="DropDownList4" runat="server" DataTextField="Sub_Name" DataValueField="Sub_Id">

</td>
<td>
:
</td>
<td>
<asp:TextBox ID="txt_Marks4" runat="server" Width="50px" onkeypress="return isNumberKey(event)">
</td>
</tr>
<tr>
<td>
<asp:DropDownList ID="DropDownList5" runat="server" DataTextField="Sub_Name" DataValueField="Sub_Id">

</td>
<td>
:
</td>
<td>
<asp:TextBox ID="txt_Marks5" runat="server" Width="50px" onkeypress="return isNumberKey(event)">
</td>
</tr>
<tr>
<td>
<asp:DropDownList ID="DropDownList6" runat="server" DataTextField="Sub_Name" DataValueField="Sub_Id">

</td>
<td>
:
</td>
<td>
<asp:TextBo

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Dee_Bee · Answer 1 · 2012-10-21T21:02:00

try this, hope it helps.

public void Dropdown()
{
try
{
DataSet ds = null;
BFDetails bfDetails = new BFDetails();
Details cmnDetails = new Details();
cmnDetails.companyId = 18;
cmnDetails.divisionId = 20;
cmnDetails.roleId = 27;
cmnDetails.userId = 702;
cmnDetails.type = "TestCases";
ds = bfDetails.TaskCaseList(cmnDetails);
DataTable dt = ds.Tables[0];
ViewState["TestCase"] = dt;
ddlTestCase.DataSource = ViewState["TestCase"];
ddlTestCase.DataTextField = "description";
ddlTestCase.DataValueField = "value";
ddlTestCase.DataBind();
ddlTestCase.Items.Insert(0, new ListItem("--Select--", "0"));

}
catch (Exception ex)
{
}