How to add control in dynamically in windows application?

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.NET3.5

I have one textbox in form in which i enter number.According to the number entered in textbox,combobox and textbox should be added in panel vertically.

Posted 25-Aug-12 0:33am

Manohar Khillare

Updated 25-Aug-12 1:38am

ridoy

v2

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[no name] 25-Aug-12 6:42am

Your question does not make any sense, "number enter in textbox combobox" makes no sense at all. But the title of your question suggests that you have not even bothered to do the least bit of research on adding controls dynamically to a form.

[no name] 25-Aug-12 6:59am

Yeah, he/she couldn't make a right English sentence.

ridoy 25-Aug-12 7:36am

i couldn't understand what you have said!

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**AmitGajjar** · Answer 1 · 2012-08-25T01:14:00

Hi,

You can Add multiple control by creating a new instance of the control.

C#

var p1 = new Panel()
var controlCount = Convert.ToInt(textbox1.Text);
for(i=0;i<controlcount;i++)>
{
  var c1 = new ComboBox();
  // set all your required property of c1 here.
  p1.Controls.Add(c1);
}

This is how you can add multiple controls in your panel. And for your second issue regarding adding your control vertically, you can use StackPanel instead of Panel control to add your dynamically created controls.

Thanks
-Amit Gajjar

Kuthuparakkal · Answer 2 · 2012-08-25T01:14:00

Solution 1

I hope you are referring Windows Form Application. If so follow the the stuff below:

C#

this.SuspendLayout();
TextBox txtbx = new TextBox();
txtbx.Text = existingTextBox.Text;
this.YourPanel.Controls.Add(txtbx);
//do similar stuff for combobox here.
this.ResumeLayout();

Posted 25-Aug-12 1:14am

Kuthuparakkal

Aarti Meswania · Answer 3 · 2012-08-25T05:30:00

C#

int gap=10;
for(i=0;i<convert.toint32(txtnum.text);i++)>
{
    combobox c = new Combobox();
    textbox t = new textbox();
    pnl.controls.add(c);
    pnl.controls.add(t);
//for dynamically set position of textbox & combobox perform some calculations like below
    t.location=new point(txtNum.Location.x,txtNum.Location.Y + (txtNum.height * i) + gap);
    c.location=new point(txtNum.Location.x+ txtNum.width + gap,txtNum.Location.Y + (txtNum.height * i) + gap);
}

Happy Coding!
:)

NandaKumer · Answer 4 · 2012-08-25T05:57:00

Solution 4

See this link
http://www.youtube.com/watch?v=5EUIyMo8maU[^]
--NDK

Posted 25-Aug-12 5:57am

NandaKumer

How to add control in dynamically in windows application?

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