input number only in a textbox

Question

1.00/5 (2 votes)

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How to input number only in a text box? And also can remove a character if I press the backspace key or delete key? I tried some code in the internet but it didn't remove a character if I press the backspace or delete key.

can you give me some code...

Posted 22-Jul-12 18:32pm

ianshack

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Comments

Sergey Alexandrovich Kryukov 23-Jul-12 2:45am

If could be one of the several different types named TextBox: in WPF, Silverlight, ASP.NET, Forms... Tag it, tell us exact type.
--SA

3 solutions

Solution 1

Try this:

VB

Private Sub NumberValidation(sender As Object, e As KeyPressEventArgs)
    If (e.KeyChar >= 48 AndAlso e.KeyChar <= 57) OrElse e.KeyChar = 8 Then
        e.Handled = False
    Else
        e.Handled = True
    End If
End Sub

Posted 22-Jul-12 18:36pm

Prasad_Kulkarni

Comments

AmitGajjar 23-Jul-12 1:09am

correct. 5+

Prasad_Kulkarni 23-Jul-12 1:15am

Thank you Amit!

ianshack 23-Jul-12 3:53am

sir, i get an error the code you gave.

Prasad_Kulkarni 23-Jul-12 3:55am

What's that?

ianshack 23-Jul-12 3:56am

Operator '>=' is not defined for types 'Char' and 'Integer'.
I got this message sir.

Prasad_Kulkarni 23-Jul-12 4:02am

Try this:


If (e.KeyChar >= 48 And e.KeyChar <= 57) Or e.KeyChar = 8 Then
        e.Handled = False
    Else
        e.Handled = True
    End If

ianshack 23-Jul-12 4:04am

Thank you sir Prasad_Kulkarni for your idea.

Prasad_Kulkarni 23-Jul-12 4:07am

Glad to hear that,Formally accept solution if it works for you..

Solution 2

You should write you own custom textbox class, as in the link here:
http://www.daniweb.com/software-development/vbnet/code/353389/numberbox-textbox-that-takes-only-number-input[^]
This allows handling the keypress event and filtering out any character that is unwanted. For the delete and backspace key: They are normally working in textboxes without any added code.

Posted 22-Jul-12 18:36pm

JF2015

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ianshack · Accepted Answer · 2012-07-22T22:03:00

Solution 3

VB

If Asc(e.KeyChar) >= 48 And Asc(e.KeyChar) <= 57 Or Asc(e.KeyChar) = 8 Then
            e.Handled = False
        Else
            e.Handled = True
        End If

I tried this code and it works.

thanks to all.

Posted 22-Jul-12 22:03pm

ianshack