C# if selected nodes is on the alphabet

Question

2.00/5 (2 votes)

See more:

this is my code to load the A-Z onto a treeview

C#

private void LoadTreeView(char start, char end)
  {
      treeView2.Nodes.Clear();
      for (char c = start; c <= end; c++)
      {
          TreeNode tn = new TreeNode(c.ToString());
          tn.Nodes.Add(new TreeNode("?"));
          treeView2.Nodes.Add(tn);
      }
  }

C#

private void Form1_Load(object sender, EventArgs e)
        {
            LoadTreeView('A', 'Z');
}

But I wanna know if i can do something like this

C#

if (treeView2.SelectedNode.Text == (LoadTreeView('A', 'Z')))
        {
//do something
        }

so if I select a nodes that's text is either A-Z it will do something, but I don't think I got that code right, on the (if) it doesn't work

Posted 13-Apr-12 23:20pm

C.CoderCreator

Add a Solution

Comments

Bala Selvanayagam 14-Apr-12 5:33am

Did a copy from your code and pasted in visual stuidio and it seems to be working ( lists nodes from "A" to "Z" each with subnode "?")

Can you please refine you question with the exact error message and at what point it happens ?

VJ Reddy 14-Apr-12 6:45am

I think Regex class can be used for this purpose as shown in Solution 4.

4 solutions

Solution 1

It definitely won't work like that - your LoadTreeView method returns a void (i.e. it returns nothing) and the if expression expects a string.

You would have to change your method quite a bit to get any sensible result - even if the whole test made any sense! How can the currently selected node be equal to a value you haven't created and loaded into your TreeView yet?

Posted 14-Apr-12 0:06am

OriginalGriff

Comments

[no name] 14-Apr-12 6:10am

I have already loaded loadtreeview in the formload and all that, what I am trying to do is when a click a letter in that treeview the letter A-Z it will do something

Solution 4

If the test is required to be done in a single statement, I think Regex class may be a better option.
The IsMatch method of System.Text.RegularExpressions.Regex class can be used as shown below:

C#

if (Regex.IsMatch(treeView2.SelectedNode.Text,"^[A-Z]$")) {
   //Do something
}

Posted 14-Apr-12 0:41am

VJ Reddy

Updated 14-Apr-12 0:58am

v2

Solution 2

C#

if (treeView2.SelectedNode.Text == "A" || treeView2.SelectedNode.Text == "B" || treeView2.SelectedNode.Text == "C" || etc)
        {
//do something
        }

Posted 14-Apr-12 0:14am

Wes Aday

Comments

[no name] 14-Apr-12 6:26am

I know I can do it that way but it takes too long and takes up allot of typing and code space, simple = better

[no name] 14-Apr-12 6:29am

Apparently you did not know that since you was comparing the node text to the result of a void function call.

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Reza Ahmadi · Accepted Answer · 2012-04-14T00:21:00

Solution 3

Hi,
You can use this code to test if selected node's text is between 'a' and 'z':

C#

string sn = treeView2.SelectedNode.Text.ToLower();
if (sn[0] >= 'a' && sn[0] <= 'z')
{
  //your code
}

I hope it helps,
Cheers

Posted 14-Apr-12 0:21am

Reza Ahmadi

Updated 14-Apr-12 0:22am

v2

Comments

VJ Reddy 14-Apr-12 6:44am

Good answer. 5!

Reza Ahmadi 14-Apr-12 6:54am

Thanks!