Creating grid dynamically

for gridview with dynamic column you need to set some property to your grid like this...

AutoGenerateColumns="true"

so it will genrate the number of column as per your data, means if your datatable contains 4 column data then the grid will show 4 column, or if it will contains 2 column data then it will display 2 columns....

like if your data table like this...

Table1
STUDENTNAME,ROLNO,CITY,DEPARTMENT

then the grid will contains this column..

or if the data will be like this..

STUDENTNAME,ROLNO

then it will show only 2 column in grid...


so for this you need to fire the select query like this. or provide datasource to grid with this criteria....

Grid Design like this...

<asp:gridview id="GridView1" runat="server" autogeneratecolumns="true" xmlns:asp="#unknown">
</asp:gridview>

So you have to create a ADO.NET Table means DATA TABLE with the number of column user enter...
and add one or needed blank row to that table and give that to gridviews data source...

DataTable dt = new DataTable();
for (int i = 0; i < 4; i++)
{
    string columnName = "COLUMN" + i.ToString();
    dt.Columns.Add(columnName);
}
DataRow dr = dt.NewRow();
dt.Rows.Add(dr);
dt.AcceptChanges();
GridView1.DataSource = dt;
GridView1.DataBind();

here i give 4 statically but you can give it user defined with use of variables....

thx for ur reply but actuallt i want to create blank column dynamically as per the user enter number of value in textbox