Help with memory leaks

There is no memory leak in function Change()

But check if the char* you passed to function Change() is pointing to dynamically allocated before calling function Change(char* pointer);

And you didn't used that char *pointer in you whole function, make sure logical correctness of his function.

you can use std::auto_ptr for avoiding memory leak.Boost smart pointers could be better alternative.

Good luck. :)

There is no memory leak in function Change()

But check if the char* you passed to function Change() is pointing to dynamically allocated before calling function Change(char* pointer); if it is dynamically allocated then don't forget to free/delete that.

And you didn't used that char *pointer in you whole function, make sure logical correctness of your function.

you can use std::auto_ptr for avoiding memory leak.Boost smart pointers could be better alternative.

Good luck. :)

Apart from the previously mentioned issues, your function will always return an empty string:

char temp[32] = "";

This reserves a char array on the stack and initializes it with the empty string, i. e. temp[0] = 0;

sprintf("%c:%c:%c:&c:%c:%c", temp[0],
    // ...
);

This command copies temp[0] to temp[0], so it stays at 0. (of course, you might in fact have meant to copy pointer[0] into temp[0] here?)

str = temp;

This assigns the string represented by temp to str. Since temp[0] == 0, temp represents the empty string, so str will be empty too.

Maybe you are mistaking the term 'memory leak' with the seemingly inexplicable vanishing of your input? Just so we can be sure we're talking about the same things: This is the definition of a memory leak[^]