Run program at startup

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Hi,
This is my code running application at startup:

C#

RegistryKey rkApp = Registry.CurrentUser.OpenSubKey("SOFTWARE\\Microsoft\\Windows\\CurrentVersion\\Run", true);
rkApp.SetValue("hadi",Application.ExecutablePath);

But my main problem is that when I run my application at startup ,the application's current directory will be C:\Documet and setting\Current User and when it wants to read from my access database it cant find it, because its in another directory.

Thanks in advance for any answers

Posted 10-Sep-10 21:53pm

hadiansari

Updated 10-Sep-10 22:40pm

v3

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Nitin S 11-Sep-10 7:00am

awesome!

2 solutions

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Abhishek Sur · Answer 1 · 2010-09-11T09:36:00

If you want it to come before Shell, you might have a quick pick into the Registry entry :

HKLM\SOFTWARE\Microsoft\WindowsNT\CurrentVersion\Winlogon

And check the key Shell.

If you change the executable to your own application, and allow your own program to start explorer, then the explorer will be totally handled by your application.

Otherwise you can install an application in startup, as it is simple to use .NET installer to install your shortcut within the Startup folders.

Kubajzz · Answer 2 · 2010-09-10T22:42:00

Solution 1

You can create a small program (or just a shell script) that will be started at startup and this program/script will be responsible for starting your main aplication.

Posted 10-Sep-10 22:42pm

Kubajzz