A program to give the following output for the given input

In order to convert a sequence of numeric characters to an integer value you need a simple loop like this:

Set value = 0
For each character:
    if character is a number:
        set tempval = character - '0'
        multiply value by 10
        add tempval to value
    else:
        print the current character value times
// continue with the remaining processing.

The below code is the complete code of Character Sequence of a given Number and the condition given that the limit is between 1-99 it does not exceeds the limit,if it does it takes the first two digit of the number
For example, if its 100=10 times it prints the respective character,This program is based on the array's positions,before you do,you have to consider it otherwise it spoil the entire code

import java.util.Scanner;
class CharSequence
{
static void PrintSeq(char c, int num) 
{
		while (num > 1) 
		{
			System.out.print(c);
			num--;
		}
}

static void ToConvert(String str) 
   {
		char c[] = str.toCharArray();
		
		for (int i = 0; i < c.length; i++) 
		{
			int val = 0;
			
			if ( c[i] >= '0' && c[i] <= '9' ) 
			{
				try 
				{
					if ( c[i + 1] >= '0' && c[i + 1] <= '9' ) 
					{
					//Used to print more than 9 values
					String a1 = String.valueOf(c[i] - 48);
					String a2 = String.valueOf(c[i + 1] - 48);
						
						val = Integer.parseInt(a1 + a2);
						
						PrintSeq(c[i - 1], val);
						
						i++;
					}
					else 
					{
						//Used to print 0-9 values
						val = c[i] - 48;
						PrintSeq(c[i - 1], val);
					}
				} 
				catch (ArrayIndexOutOfBoundsException ex) 
				{
					val = c[i] - 48;
					PrintSeq(c[i - 1], val);
				}				
			} 
			else 
			{
				System.out.print(c[i]);				
			}
		}
	}
	public static void main(String args[]) throws Exception
	{
		Scanner s=new Scanner(System.in);
		
		String wrd=s.nextLine();
		ToConvert(wrd);
	}
}