Why my output is zero in float?

Question

1.00/5 (1 vote)

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C++

#include<stdio.h>
int main()
{
    float num1,num2;
    printf("Enter 1,2 float: ");
    scanf("%.2f %.2f",&num1, &num2);
    printf("Result:%.2f %.2f\n",num1,num2);
    return 0;
}

What I have tried:

Output is 0.00 whatever the input I give. Why can't I find the output I give in inout?.in codeblock I tried.

Posted 11-Nov-23 19:40pm

Jannatul Tamanna

Updated 11-Nov-23 21:02pm

KarstenK

v2

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3 solutions

Solution 3

Have also a look at the documentation: function scanf - cppreference[^].

Posted 12-Nov-23 20:05pm

CPallini

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Richard MacCutchan · Accepted Answer · 2023-11-11T21:38:00

Solution 1

You cannot specifiy width or precision values on numbers that are to be read. The scanf function will attempt to read all valid characters (digits and decimal point) that make up a number, and convert it to the appropriate type. So change your scanf line to:

C++

scanf("%f %f",&num1, &num2);

Posted 11-Nov-23 21:38pm

Richard MacCutchan

Comments

CPallini 13-Nov-23 2:05am

5.

M Imran Ansari · Accepted Answer · 2023-11-12T02:07:00

Solution 2

The precision specifier (%.2f) is used in the 'printf' function instead of 'scanf' to control the number of decimal places when displaying the float values.
For example, %10.4f displays a number at least 10 characters wide in total and four of them are decimal places.

Posted 12-Nov-23 2:07am

M Imran Ansari

Comments

CPallini 13-Nov-23 2:05am

5.