You are given a word "medha". You can speak this word repeatedly only upto N letters. (N is user input). Print the final string that you need to speak.

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You are given a word "Medha". You can speak this word repeatedly only upto N letters. (N is user input).
Print the final string that you need to speak.Eg:
N=8
Output-
MedhaMed
I am getting an exception in my code.

Input the maximum no: of letters upto which u want to speak the word repeatedly:

Exception in thread "main" java.util.NoSuchElementException
	at java.base/java.util.Scanner.throwFor(Scanner.java:937)
	at java.base/java.util.Scanner.next(Scanner.java:1594)
	at java.base/java.util.Scanner.nextInt(Scanner.java:2258)
	at java.base/java.util.Scanner.nextInt(Scanner.java:2212)
	at medhaword.main(medhaword.java:10)

What I have tried:

Java

import java.util.*;
import java.io.*;
import java.lang.*;
public class medhaword
{
    public static void main(String[] args)
    {
        Scanner sc=new Scanner(System.in);
        System.out.println("Input the maximum no: of letters upto which u want to speak the word repeatedly:");
    int N=sc.nextInt();
         String s="Medha";
        int x=s.length();
        int noofrepetitions=N/x;
        int remletters=N%x;
        String t="";
        for(int i=0; i<noofrepetitions; i++)
="" {
="" t+="s;
" }
="" if(remletters="">0)
        {
            t+=s.substring(0, remletters);
        }
        System.out.println(t);
    }
}

Posted 25-Jun-23 0:05am

Abhinav Kishore M

Updated 25-Jun-23 0:25am

OriginalGriff

v2

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Comments

Abhinav Kishore M 25-Jun-23 6:16am

why this need for =""?

Dave Kreskowiak 25-Jun-23 11:07am

It's a bug in CP when you paste code.

Abhinav Kishore M 25-Jun-23 6:19am

I am getting this exception:
Exception in thread "main" java.util.NoSuchElementException
at java.base/java.util.Scanner.throwFor(Scanner.java:937)
at java.base/java.util.Scanner.next(Scanner.java:1594)
at java.base/java.util.Scanner.nextInt(Scanner.java:2258)
at java.base/java.util.Scanner.nextInt(Scanner.java:2212)
at medhaword.main(medhaword.java:10)

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OriginalGriff · Accepted Answer · 2023-06-25T00:25:00

The code you provide doesn't compile as shown, I have fixed what it looks like it should be (and indented it correctly):

Java

import java.util.*;
import java.io.*;
import java.lang.*;
public class Main
{
	public static void main(String[] args) 
	{
        Scanner sc=new Scanner(System.in);
        System.out.println("Input the maximum no: of letters upto which u want to speak the word repeatedly:");
        int N=sc.nextInt();
        String s="Medha";
        int x=s.length();
        int noofrepetitions=N/x;
        int remletters=N%x;
        String t="";
        for(int i=0; i<noofrepetitions; i++)
        {
            t+=s;
        }
        if(remletters>0)
        {
            t+=s.substring(0, remletters);
        }
        System.out.println(t);	
	}
}

If I run that in an online Java IDE (Online Java Compiler - online editor[^]) it works fine:

Result

Input the maximum no: of letters upto which u want to speak the word repeatedly:
8
MedhaMed


...Program finished with exit code 0
Press ENTER to exit console.

So ... the problem is something in the environment at your end, and we have no access to that at all (or even any idea what it might be!)