How do I get out of the infinite loop although I have tried getting out using break?

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I wanted to create a program that randomly assigns the user a group if the name is in the list and if not it should repromt the user but once i am done with the number of names in the lsit it should stop but it keeps on promting how should i get out of it.........

Python

  1  import random
  2  names=["ayush","bhargav","nayan","money","niju"]
  3  while True:
  4      for name in names:
  5          name=input("what is your name: ")
  6          name=name.casefold()
  7          group=random.randint(1,5)
  8          if name in names:
  9              print(name,"your group is",group)
 10          break
 11      else:
 12             continue

What I have tried:

tried using break but not working

Posted 9-Apr-23 6:52am

Prayash Bhuyan

Updated 9-Apr-23 7:54am

0x01AA

v3

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0x01AA 9-Apr-23 13:31pm

Now I'm far away from knowing phyton... but is it not only the break in line no. 10 which needs to be 'inserted' ?
How I hate languages depending on intendations :-)

Dave Kreskowiak 9-Apr-23 15:59pm

The break statement gets you out of the inner-most loop, be it a "for" or "while". You would be much better off using a flag to get you out of the outer "while" loop.

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Richard MacCutchan · Answer 1 · 2023-04-09T07:54:00

The Break statement belongs to the preceding if, so it needs to be indented to the same level as the print.

Python

if name in names:
    print(name,"your group is",group)
    break

[edit]
A simplified solution is:

Python

import random
names=["ayush","bhargav","nayan","money","niju"]
while True:
    whoareyou=input("what is your name: ")
    if whoareyou in names:
        group=random.randint(1,5)
        print(whoareyou,"your group is",group)
        break
    else:
        print(whoareyou, "is not a valid name, try again")

[/edit]

Mike Hankey · Answer 2 · 2023-04-09T07:28:00

Solution 1

Use a flag in your while statement;

Python

active = True
while active:
.
.
.
  if name in names:
    print(name,"your group is",group)
    active = False

Posted 9-Apr-23 7:28am

Mike Hankey

Comments

Prayash Bhuyan 9-Apr-23 23:54pm

Hey the flag actually worked but not exactly i am able to break out of the loop but what i want is that when the name is not in the list the for loop shouldnot run it should just promt the user but here it considering it to be one iteration can you help?

Prayash Bhuyan 10-Apr-23 0:35am

For doing what i intended to do i cehcked the if statement first so it is not considering it to be interation but now the problem is if one name is in ht elist it prints all the name together and doesnot ask the user for names again and again

import random
names=["ayush","bhargav","nayan","money","niju"]
active=True
while active:
name=input("what is your name: ")
if name in names:
for name in names:
name=name.casefold()
group=random.randint(1,5)
print(name,"your group is",group)
active=False
else:
continue

Richard MacCutchan 10-Apr-23 4:10am

See my solution above, for the correct usage of the break statement. You can also remove the else and continue as they are not necessary.

Prayash Bhuyan 10-Apr-23 4:49am

I got what you said but what i am saying is that that works fine but i want the for loop to run only when the name is in the lsit and if not it should repromt the user but the promting message shouldnot be counted as iteration but in my programe it is counting it as a iteration...

Prayash Bhuyan 10-Apr-23 4:50am

Also once the for loop runs if the user enters a wrong input it should not also count that as an iteration

Richard MacCutchan 10-Apr-23 5:09am

See my updated solution.

Prayash Bhuyan 10-Apr-23 9:18am

I saw your solution and i really appreciate you trying to help me but this is also what i donot want i want suppose the list is [ayush,nayan,bhargav,niju,money]
the program runs and promts
type a name: ayush
ayush you group is 5
and then it shouldnot break it should be like
type a name:ayush
ayush your group is 5
type a name;bhargave
bhargav your group is 1
type a name: aaa(since it is not in the lst again promt type a name)
and this type a name promt should end only when all the write names in the list is over even in between ar in start the user enters a wrong name it should not consider it as a iteration of it owns

Richard MacCutchan 10-Apr-23 9:21am

Well that is really a different issue. I think you need to post a different question, but make sure you explain exactly what the program is supposed to do.

Prayash Bhuyan 10-Apr-23 9:26am

okay and thank you very much

How do I get out of the infinite loop although I have tried getting out using break?

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