Return the sum of the odd numbers in C

Question

1.00/5 (1 vote)

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I have
Int RangeSum(int start, int end)
{
Int i, sum=0;

Some one can explained for me how I need to do this?
It should return the sum of odd numbers within the range

What I have tried:

I tried with for function but it’s doesn’t work, how I can convert it in if function? Or maybe have another way for beginners? Without scanf and printf

for (i=0; I<10; I++)
{
If (i%2!=0)
{
Sum=sum+i;
}
}
Return sum;

Posted 8-Dec-22 3:18am

Member 15858418

Updated 8-Dec-22 4:33am

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2 solutions

Solution 1

I guess your code is this:

C++

Int RangeSum(int start, int end) {
	Int i, sum=0;
	for (i=0; I<10; I++) 	{
		If (i%2!=0) 		{
			Sum=sum+i;
		}
	}
	Return sum;
}

You want the sum of odds between start and end.
The problem is that you don't use those variables in the for loop.
Your for loop goes from 0 to 10, and you want the loop to go from start to end.
Solution should be rather easy.

Posted 8-Dec-22 3:48am

Patrice T

Comments

Richard MacCutchan 8-Dec-22 10:14am

All those capital letters are sure going to confuse the C compiler.

Patrice T 8-Dec-22 10:21am

Just copied code from question :) and gave hint about the solution.
Never meant to do all the work.

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Richard MacCutchan · Accepted Answer · 2022-12-08T04:33:00

Your code is broadly correct, but all those capital letters in type and variable names will cause compilation errors. Also, your for loop needs to be from start to end; I show it as inclusive of the end value.

C++

int RangeSum(int start, int end)
{
    int i, sum=0;
    for (i = start; i <= end; i++)
    {
        if (i % 2 != 0)
        {
            sum = sum + i;
        }
    }
    return sum;
}