How do I match integers with equivalent strings via C# LINQ select operator

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I need to Produces a sequence of strings representing the string version of a sequence of integers using LINQ Select or SelectMany keyword
Thank You in advance!

I need the output to be:
"five",
"four",
"one",
"three",
"nine",
"eight",
"six",
"seven",
"two",
"zero",

update:
Solved Thank to Maciej Los

int[] numbers = {5, 4, 1, 3, 9, 8, 6, 7, 2, 0};
            string[] strings = {"zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"};

            IEnumerable<string> stringSequence = numbers.Select(x => strings[x]).ToList();

            return stringSequence;

What I have tried:

public static void Main(string[] args)
        {
            int[] numbers = { 5, 4, 1, 3, 9, 8, 6, 7, 2, 0 };
            string[] strings = { "zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine" };

            IEnumerable<string> stringSequence = numbers.Select((n, index) => n.ToString == strings[index]); // I know this is wrong but can't figure out how to do it correctly.

// I also tried: 
IEnumerable<string> stringSequence = numbers.Select(x => x.ToString());

Console.WriteLine(stringSequence);
    }

Posted 28-Feb-22 3:24am

LuckyChloe

Updated 28-Feb-22 4:03am

v4

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Comments

Luc Pattyn 28-Feb-22 10:20am

Sorry, in the line

IEnumerable<string> stringSequence = numbers.Select(x => strings[x]).ToList();

calling ToList() does not make any sense as you are assigning to stringSequence which is an IEnumerable, and your numbers.Select() already is an IEnumerable, so all memory and CPU cycles spent to ToList() are wasted.

:)

PIEBALDconsult 28-Feb-22 10:26am

You could also look into using an enum.

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Maciej Los · Accepted Answer · 2022-02-28T03:56:00

I'd use Dictionary[^] object:

C#

Dictionary<int, string> WordNum = new Dictionary<int, string>();
WordNum.Add(0, "zero");
WordNum.Add(1, "one");
WordNum.Add(2, "two");
WordNum.Add(3, "three");
WordNum.Add(4, "four");
WordNum.Add(5, "five");
WordNum.Add(6, "six");
WordNum.Add(7, "seven");
WordNum.Add(8, "eight");
WordNum.Add(9, "nine");

int[] numbers = { 5, 4, 1, 3, 9, 8, 6, 7, 2, 0 };


var result = numbers.Select(x=> WordNum[x]).ToList();