Whats wrong with this code of mine?

Question

1.00/5 (1 vote)

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C

#include<stdio.h>
#include<stdbool.h>
main()
{
	int age;
	char name;
	printf("what is your name? ");
	scanf("%s",&name);
	printf("what is your age? ");
	scanf("%d",&age);
    printf("you're name is %s and you're age is %d.", name , age);
    return 0;
}

What I have tried:

i have tried all the ways i could but i still not able to get the last print statement.

Posted 10-Jan-22 5:55am

Anushka Sharma 2022

Updated 10-Jan-22 20:13pm

CPallini

v2

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Comments

jeron1 10-Jan-22 12:00pm

You have defined name as a single character, it should be an array of characters, large enough for the longest name you expect plus 1 for the null terminator.

Richard Deeming 10-Jan-22 12:19pm

Aside from the code errors, it's "your name", not "you're name". :)

"Your" is the possessive - the thing belonging to you.

"You're" is a contraction of "You are".

"You are name is ..." and "you are age is ..." are not valid English.

2 solutions

Solution 2

See, for instance: Strings in C (With Examples)[^].

Posted 10-Jan-22 20:13pm

CPallini

Comments

Maciej Los 11-Jan-22 6:54am

5

CPallini 11-Jan-22 6:56am

Thank you!

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steveb · Accepted Answer · 2022-01-10T06:08:00

Solution 1

C++

char name;

Is what is wrong with your code. char is not a string but a byte sized integer.
you need to change that declaration to

C++

char name[50];

That will be a character array that can hold 49 characters plus a null terminator.

Posted 10-Jan-22 6:08am

steveb

Comments

CPallini 11-Jan-22 2:09am

5.

Maciej Los 11-Jan-22 6:54am

5