When executing unavailable file exception occurs but after that error is occuring! ! !

Question

0.00/5 (No votes)

See more:

#Write a Python program to copy the contents of a file to another file .

Python

def file():
 file= input("Enter file name(test.txt): ")   
 try:
  with open(file) as f:
    with open("another.txt", "w") as f1:
        for line in f:
            f1.write(line) 
    print("Contents of file",file,"is copied to another file successfully")        
 except:
    print('File cannot be opened:', file)
    file()
file()

What I have tried:

Exception has occurred: TypeError
'str' object is not callable

with open(file) as f:

During handling of the above exception, another exception occurred:

file()

file()

Posted 2-Jan-22 6:19am

Joshna J U

Updated 2-Jan-22 7:09am

OriginalGriff

v2

Add a Solution

3 solutions

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

OriginalGriff · Accepted Answer · 2022-01-02T06:23:00

Solution 1

Look at your code:

Python

def file():
 file= input("Enter file name(test.txt): ")   
 try:
  ...
 except:
    print('File cannot be opened:', file)
    file()
file()

So if the code reaches the exception, it prints a message, and then recursively calls the function it's already executing which does exactly the same thing again. And again. And again ...

Why are you calling file in the exception handler code?

Posted 2-Jan-22 6:23am

OriginalGriff

Comments

Joshna J U 2-Jan-22 12:28pm

Why are you calling file in the exception handler code?
because, again the code should repeat until user enters valid file name.

OriginalGriff 2-Jan-22 12:41pm

So use a loop, not recursion.
And do yourself a favour: don't call two different things the same name - it makes it a lot harder to read!

0x01AA · Accepted Answer · 2022-01-02T06:48:00

What OG means is (I think at least) better use something like this:

def file():
 while True:
   file= input("Enter file name(test.txt): ")   
   try:
    if file == "":
     break
    with open(file) as f:
      with open("another.txt", "w") as f1:
          for line in f:
              f1.write(line) 
      print("Contents of file",file,"is copied to another file successfully")  
      break
   except:
      print('File cannot be opened:', file)
     
file()

I hope it helps.

Luc Pattyn · Accepted Answer · 2022-01-02T07:09:00

Solution 3

you shouldn't use the same name for a function and one of its variables.

Even if it would be allowed in your programming language, it always is a bad practice, as it confuses everyone.

Hint: use nouns for variables, and verbs or verb+noun (e.g. copyFile or copyfile) for functions.

:)

Posted 2-Jan-22 7:09am

Luc Pattyn

Updated 2-Jan-22 7:50am

v3

Comments

0x01AA 2-Jan-22 13:28pm

Hard to find the right way PEP 8 -- Style Guide for Python Code | Python.org[^] ;)

Luc Pattyn 2-Jan-22 13:45pm

As the error message said 'str' object is not callable I would guess that language pools function and variable names; however I don't need to know for sure, as I would never do that in the first place.