How do I write this code,

Question

1.00/5 (1 vote)

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make a program with output like this (right align
)

6
56
456
3456
23456
123456

What I have tried:

#include<iostream>
using namespace std;
int main(){
	int i, j;
	int n = 6;
	
	for (i=1; i<=n; i++)
	{
		for (j=1; j<=i; j++)
		{
			cout<<i;
		}
		cout<<endl;
	}
	return 0;
}

Posted 22-Nov-21 21:25pm

Firdaus Nandu

Updated 22-Nov-21 22:02pm

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Richard MacCutchan 23-Nov-21 3:52am

The outer loop needs to go in reverse order from 6 down to 1. The inner loop needs to go from the current value of the outer loop index forwards to 6.

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TheRealSteveJudge · Accepted Answer · 2021-11-22T22:01:00

First of all you should learn to use a debugger
in order to see what your programme is doing.

If you are using Visual Studio you can follow this tutorial:
Tutorial: Debug C++ code - Visual Studio (Windows) | Microsoft Docs[^]

Your current output is

Your outer loop counts from 1 to 6.

You must use an outer loop counting from 6 to 1 instead.
The inner loop must count from the current "i" to 6.

Have a look at this:

#include<iostream>
using namespace std;

int main(){
	int maximum = 6;
	
	for(int i=maximum; i>0; i--)
	{
	    for(int j=i; j<=maximum; j++)
	    {
	        cout << j;
	    }
	    
	    cout << endl;
	}
	
	return 0;
}

CPallini · Accepted Answer · 2021-11-22T22:02:00

In order to right align the numbers (without using cout facilities) you have just to precede your number with the right amount of blanks.
Moreover your current code simply duplicates i.
I give you a possible incipit:

C++

#include<iostream>
using namespace std;
int main()
{
  const int N = 6;

  for (int start=N; start>0; --start)
  {
    int items = (N-start+1);
    // TODO: here output '(N-items)' blanks, then output 'items' digits, then output a newline.
  }
  //...

How do I write this code,

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