How to copy a long array passed as argument to a std::list

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Hello Everyone,

I am trying to copy an array of long into a std::list or std:vector.

I have the following code sample:

C++

#include "stdafx.h"
#include <iostream>
#include <list>
#include <iterator>

using namespace std;

class Channels
{
public:
void Configure(long channels[])
{
_channels <= channels; //..... copy channels to _channels
}

private:
   std::initializer_list<long> _channels{};
}

Could you please point me if I am on the right track.

Thank you very much in advance.
Best regards.
MiQi

What I have tried:

I have tried the following but not sure if this is the correct way:

C++

#include "stdafx.h"
#include <iostream>
#include <list>
#include <iterator>

using namespace std;

class Channels
{
public:
void Configure(std::initializer_list<long> chans, int size)
{
   _channels = std::initializer_list<long>{ chans };
}

private:
   std::initializer_list<long> _channels{};
}

void main()
{
   long channels[] {1, 3 , 5};
   Channels channel;
   Channel.Configure(channels);
}

The sample code compiles happily.

Posted 15-May-19 7:31am

SuperMiQi

Updated 15-May-19 10:30am

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John R. Shaw · Answer 1 · 2019-05-15T10:30:00

Solution 1

How about a simple old school solution.
1. Pass the size of the array along with the array; otherwise you do not know its size.
2. Just assign it to a member variable.

This should do the trick:

class Channels
{
public:
void Configure(long channels[], size_t size)
{
    _channels.assign(channels, channels+size);
}

private:
   std::vector _channels;
}

Posted 15-May-19 10:30am

John R. Shaw

Comments

SuperMiQi 15-May-19 17:52pm

Thank you very much. It was indeed a good approach.
I will now post my entire code set to see if I am on the right path. It works but maybe am I missing important keys.
Thanks again.