Comments by debil123 - CodeProject

debil123 17-Apr-13 10:49am View

But both copy constructors are the same. why not to implement single generic one?
I mean- that's the original question is all about.

debil123 17-Apr-13 10:08am View

In that way you have to implement copy constructor instead of the assignment operator for each iterator type.
I thought it is obvious from my original post.

debil123 14-Apr-13 9:42am View

It does do something that the base class can't do. The base class can't check the someCheck(). That's the whole point. All this needed for the begin(), end(), erase() and other functions which the iterator itself doesn't know how to do.

debil123 14-Apr-13 2:45am View

it doesn't compile. assignment operator, although its trivial should be added to support the assignment needed by my begin() function.

debil123 13-Apr-13 17:51pm View

It is not the answer I was looking for. Did you read the "p.s." thing? It states that the example is just to clarify my question- how to template the inherited class.

debil123 13-Apr-13 17:49pm View

this:

template< class Item > class directedListTypeIter : public typename std::list<item>::iterator

does define which type of iterator it is. it is forward iterator.

but- as I said, the solution you posted in the beginning can solve my issue. but I am not interested in solving this particular issue of creating forward, or reverse iterator. I am interested in finding how to template inheritance.
I mean- why this:
directedListTypeIter& operator=(realIter &constructorIter){
((realIter*)this)->operator=(constructorIter);
return *this;
}
is ambiguity?

debil123 11-Apr-13 12:03pm View

Thanku for your answer. It may be a solution for the example issue.
But, it is not applicable in my case.
1. I can't use myContext instead of std::list.
2. when compiling templated code, I understand that the compiler duplicates the code. It means that both types of iterators can't share a single list. Because it defined twice. But, maybe we don't need that definition at all.

Anyway, it is not the answer I was looking for.
Did you read the "p.s." thing? It states that the example is just to clarify my question- how to template the inherited class.

Comments by debil123 (Top 7 by date)