Comments by Member 8233601

Member 8233601 10-Jan-14 8:26am View

could you please suggest any solution to achieve this functionality.

Member 8233601 7-Nov-13 8:46am View

is it possible to get rowindex on right click of datagrid cell

Member 8233601 7-Nov-13 7:47am View

undefined object

Member 8233601 7-Nov-13 7:45am View

already tried this but wont work.please tell how could i get rowindex on right click of any cell of datagrid

Member 8233601 7-Nov-13 5:27am View

please help me out i am in big trouble

Member 8233601 7-Nov-13 5:26am View

Deleted

<asp:GridView ID="Grd_Stock" ForeColor="Black" PagerStyle-CssClass="PagerStyle" runat="server"
RowStyle-CssClass="RowStyle" AllowSorting="true" GridLines="None" CssClass="GridViewStyle jk"
AlternatingRowStyle-CssClass="AltRowStyle" AutoGenerateColumns="False" AllowPaging="true"
PageSize="50" OnPageIndexChanging="Grd_Stock_PageIndexChanging" ShowFooter="false"
OnRowCreated="gvHover_RowCreated" Width="1232px" PagerStyle-HorizontalAlign="Center"
OnSorting="Grd_Stock_Sorting" OnRowDataBound="Grd_Stock_RowDataBound">
<PagerSettings Mode="NumericFirstLast" Position="TopAndBottom" PageButtonCount="4"
FirstPageText="First" LastPageText="Last" />
<emptydatatemplate>
<div class="grdempt">
No Record Found...</div>

<columns>

<asp:TemplateField HeaderText="Creation Date" SortExpression="creation_date">
<itemtemplate>
<asp:Label Width="133px" Text='<%#dat_format_ddmmyy(Eval("creation_date") )%>' ToolTip="Createion Date"
ID="txt_product_name" runat="server">

<itemstyle width="200px">
<HeaderStyle Font-Bold="true" />

<asp:TemplateField HeaderText="Cust Name" SortExpression="lead_name">
<itemtemplate>
<asp:LinkButton ID="lbtn_name" Width="200px" CssClass="grdlinkbtn" runat="server"
OnClick="lbtn_name_click" Text='<%#Eval("lead_name") %>' CausesValidation="false" >
<asp:HiddenField ID="hd_lead_code" Value='<%#Eval("lead_code") %>' runat="server" />

<itemstyle width="200px">
<HeaderStyle Font-Bold="true" />

<asp:TemplateField HeaderText="Agent Name" SortExpression="created_by_name">
<itemtemplate>
<asp:Label ID="txt_company" Text='<%#Eval("created_by_name") %>' runat="server" Width="200px">

<itemstyle width="200px">
<HeaderStyle Font-Bold="true" />

<asp:TemplateField HeaderText="Lead Rating" SortExpression="lead_rating_desc">
<itemtemplate>
<asp:Label ID="lbl_rating" Text='<%#Eval("lead_rating_desc") %>' runat="server" Width="50px">

<itemstyle width="200px">

Member 8233601 24-Oct-13 6:15am View

hours1 and hours2 is just an example, may be more than five hours be there and i am summing up all that hours. i just want to convert 18.83 into 18.50

Member 8233601 22-Oct-13 4:18am View

i need it in crystalreport.please provide me any solution how to do it in crystal report

Member 8233601 20-Jun-13 0:56am View

problem is onload of form combo1.selectedindexchanged get fired after combo1.datasource=ds.table[0]

Member 8233601 18-Jun-13 3:23am View

5+

Member 8233601 3-Jun-13 2:20am View

OnClientClick="return getpid()"

Member 8233601 3-Jun-13 2:04am View

thnx

Member 8233601 1-Jun-13 12:09pm View

can we create instance in static method?????

Member 8233601 29-May-13 9:14am View

Member 8233601 29-May-13 8:52am View

it's not working.
ok sir let know is it possible to achiev ethis using web method

Member 8233601 29-May-13 8:39am View

no there is no error but div still hides after event

Member 8233601 29-May-13 8:30am View

still problem continues..

Member 8233601 29-May-13 8:25am View

so their is no need to call onclientclick

Member 8233601 29-May-13 8:24am View

Deleted

so their id no need to call onclientclick

Member 8233601 29-May-13 8:02am View

no sir need just opposite of this
after coming back from event i need to show this div

Member 8233601 29-May-13 7:27am View

sir onclientside event took first and then server side event occur. hows is possible

Member 8233601 29-May-13 6:48am View

end of this event

Member 8233601 29-May-13 6:35am View

Page.RegisterStartupScript("OnLoad", "<script>Divshow();</script>");

function Divshow()
{
document.getElementById('MSGd').style.display = "block";
}
bt it's not working
please suggest me any solution i m need

Member 8233601 21-May-13 1:32am View

Hi,john i got the answer.
you are right we have to mention the else condition.
thanx a lot....

Member 8233601 20-May-13 8:02am View

still i am getting this error
Object reference not set to an instance of an object.

Member 8233601 20-May-13 7:43am View

actually i want to do something like this
Declare @result tinyint
@result=delete from OPDPatient where REGNO=@PID
if(@result>0)
@result=delete from OPDPatient where REGNO=@PID

please help me by providing this type of solution

Member 8233601 20-May-13 7:37am View

so what should i pass if frmdate =""

Member 8233601 20-May-13 7:10am View

As you can see i already initialise all the input parameters in my stored procedure. so if frmdate="" it will automatically initialised by default value declared in sp.

Member 8233601 20-May-13 2:40am View

I have corrected this mistake but still i am getting the same error

Member 8233601 21-Mar-13 12:07pm View

could you please elaborate your solution

Member 8233601 21-Mar-13 12:06pm View

i want to do only for my knowledge. I know this is not a reliable way to distribute the software. please provide any solution.....

Member 8233601 28-Jan-13 6:42am View

ok leave i solve this problem
can u tell how to make string like this 20,30,40 from arr[20,30,40] i.e my arraylist contain 3 or 4 elements and i want to make sting out of it. I try it like this
foreach(string h in arr)
{
labl += h+",";
}
it come out with result like this 20,30,40,

Member 8233601 28-Jan-13 6:37am View

my arraylist is populated at the runtime...

Member 8233601 28-Nov-12 7:02am View

where should my exe file..

Member 8233601 20-Sep-12 3:11am View

plz help with code i am unable ti find solution...

Member 8233601 18-Sep-12 1:23am View

will u plz eloborate....

Member 8233601 25-Aug-12 5:57am View

i am using acess 2003 database so provide me connction string for that..

Member 8233601 24-Aug-12 6:22am View

thnx...

Member 8233601 24-Aug-12 3:19am View

I USED THE FOLLOWING CODE IT WORKS FINE BUT NUMS LOCK WORK FOR ONLE ONCE i.e if my nums lock is off IT SHOW NUMS IS OFF BUT AFTER THAR IT SHOWS THE SAME STATUS
private void Form1_KeyDown(object sender, KeyEventArgs e)
{
if ((e.KeyCode & Keys.KeyCode) == Keys.CapsLock)
{
if (Control.IsKeyLocked(Keys.CapsLock))
this.toolStripStatusLabel3.Text = "Caps is activated.";
else
this.toolStripStatusLabel3.Text = "Caps is Deactivated.";
}

else if ((e.KeyCode & Keys.KeyCode) == Keys.NumLock)
{
if (Control.IsKeyLocked(Keys.NumLock))

this.toolStripStatusLabel5.Text = "NumLock is activated.";

else

this.toolStripStatusLabel5.Text = "NumLock is Deactivated.";

}

}

Member 8233601 23-Aug-12 4:40am View

thnx a lot..

Member 8233601 23-Aug-12 0:31am View

my connectionstring is:
OleDbConnection con = new OleDbConnection("Provider=Microsoft.Jet.OLEDB.4.0;Data Source=|DataDirectory|/furnituredb.mdb");
I put it in bin of my project. now if i give the connection string as you mention
will it work...

Member 8233601 22-Aug-12 1:07am View

and what if i want to share my application so that everyone of us work on independent form...

Member 8233601 18-Aug-12 4:15am View

sir i have put my mdb file in debug folder and i am using windows7 which is currently out of service. now plz help me out through each step o solve this prblm..

Member 8233601 9-Aug-12 1:19am View

how i come to which row to lock because i dont know which id is working at which instance of time. please provide me nay link or somr code if u have...

Member 8233601 9-Aug-12 1:01am View

sir its fine, but suppose candidate A and candidate B start working at the same time. candidate A work on ID 001 so how can i check that candidate B should not work on ID 001 at that time or any later time. I just want to stop working of multiple candidate on the same id while they are working simultaneously or at any later time

Member 8233601 1-Aug-12 0:55am View

error is shown in this line:this.ReportViewer1.LocalReport.DataSources.Add(rptDataSource);

Member 8233601 31-Jul-12 0:41am View

tell me solution boss

Member 8233601 31-Jul-12 0:25am View

please provide me proper instruction with any practical demo..

Member 8233601 24-Jul-12 3:38am View

plz provide me code i m in need

Member 8233601 11-Jul-12 7:24am View

flipcart.com

Member 8233601 11-Jul-12 6:59am View

Actually it's client requirement to change color of image what ever the texture selected by user at runtime.plz help me i m in need....

Member 8233601 27-Jun-12 8:23am View

if i set AlawaysCreate to false, i don't think their is any effect on setup.

Member 8233601 14-Jun-12 8:58am View

can u plz tell me step by step procedure...

Member 8233601 4-Jun-12 2:06am View

when i right click on demo reference it shows two option:Add Reference and Add service reference

Member 8233601 7-May-12 3:15am View

hello rahul sorry to embarrass you actually i am new in this field so can you please tell me step by step procedure to create this trail version...

Member 8233601 7-May-12 1:05am View

OleDbConnection conn = new OleDbConnection("Provider=Microsoft.Jet.OLEDB.4.0;Data Soure=|DataDirectory|/Schooldb.mdb");

Member 8233601 5-May-12 9:25am View

i made it but still it not work..

Member 8233601 25-Apr-12 1:21am View

i have problm in retriving img from database..

Member 8233601 20-Apr-12 3:16am View

can u tell me how to make a single column of girdview readonly.

Member 8233601 18-Apr-12 8:50am View

can u plz tell me what visual web developer.is it part of visual studio 2010 or we have to download it seperately?

Member 8233601 18-Apr-12 1:47am View

In my Database(Schooldb) i have a table named ClassReg with columns ID(pk),Subject,Class_name,Section,Start_time,End_time.I jst wna show subjects for that particular class and section within a pannel in winform of visual studio 2008....

Member 8233601 17-Apr-12 3:03am View

its work fine we cannot made multiple changes

Member 8233601 17-Apr-12 1:41am View

thanks 4 every thing...

Member 8233601 17-Apr-12 1:12am View

plz provide me proper code.

Member 8233601 17-Apr-12 1:07am View

its not working...still the same error..

Member 8233601 17-Apr-12 1:07am View

plz provide me code i m in need...

Member 8233601 16-Apr-12 8:05am View

plz tell me complete procedure..

Member 8233601 16-Apr-12 8:05am View

no

Member 8233601 16-Apr-12 6:22am View

I am getting this error:

Update requires a valid UpdateCommand when passed DataRow collection with modified rows.

Member 8233601 16-Apr-12 6:15am View

right now i m using ti code:

private void Teacher_Routine_Load(object sender, EventArgs e)
{
OleDbDataAdapter adpt = new OleDbDataAdapter("select * from ClassAdmin Order by Class_name", conn);
OleDbCommandBuilder cbld = new OleDbCommandBuilder(adpt);
conn.Open();

adpt.Fill(ds);
dataGridView1.DataSource = ds.Tables[0];
//conn.Close();

}

private void button1_Click(object sender, EventArgs e)
{
adpt.Update(ds);
}

Member 8233601 10-Apr-12 3:31am View

I am using this code to load pictureBox1 on Button2_click event:

try
{
OpenFileDialog of = new OpenFileDialog();

DialogResult d = of.ShowDialog();

of.Filter = "Image Files(*.jpg; *.jpeg; *.gif; *.bmp)|*.jpg; *.jpeg; *.gif; *.bmp";
if (d == DialogResult.OK)
{
pictureBox1.BackgroundImage = Image.FromFile(of.FileName);
imaeg = of.FileName;
}
}
catch (Exception ex)
{
MessageBox.Show("upload only jpg image!!");

}
}

On save_click button event:

OleDbConnection conn = new OleDbConnection("Provider=Microsoft.Jet.OLEDB.4.0;Data Source= |DataDirectory|/Schooldb.mdb");
OleDbCommand cmd = new OleDbCommand("insert into Student values(@Myimage)",conn);
cmd.Parameters.AddWithValue("@Myimage", imaeg);
}

My image get saved as Long Binary Data in Access2003 database.On login page i want to show image in picurebox on show_click event.
plz rply as soon as possible!!

Member 8233601 9-Apr-12 1:33am View

i need it for windows application

Member 8233601 6-Apr-12 2:37am View

while establishing connection with local database(.sdf) i am getting this error:
A network-related or instance-specific error occurred while establishing a connection to SQL Server. The server was not found or was not accessible. Verify that the instance name is correct and that SQL Server is configured to allow remote connections. (provider: SQL Network Interfaces, error: 26 - Error Locating Server/Instance Specified)

plz help..

Member 8233601 6-Apr-12 2:23am View

how do i create connection with local database(.sdf),i mean connection string

Member 8233601 6-Apr-12 2:18am View

how do i create connection with local database(.sdf),i mean connection string

Member 8233601 6-Apr-12 2:10am View

how do i create connection with local database(.sdf)

Member 8233601 6-Apr-12 1:58am View

connection string for .sdf database

Member 8233601 6-Apr-12 1:47am View

how would i knw which edition i have?i m working on visual studio 2008 and i dont want to create database on sql server 2005.

Member 8233601 4-Apr-12 8:37am View

this link is fine but i dont want to create database in any particular drive.its all upto user when he/she instal my application.i need that when my application get install everything will be created at path specified by the user.

Comments by Member 8233601 (Top 79 by date)