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Comments by Akshay 007 (Top 4 by date)

Akshay 007 25-Nov-13 21:34pm View    
The Data Types are CHARACTER of length 30, INTERGER (4 byte), FLOAT (4 byte) and CHARACTER of length 30.
The character is similar to FORTRAN 77, where if assign the variable with length 30 then 30 characters will be printed, and the values at indexes can be alphanumeric or blanks. The key here is that even blanks will be printed.
Akshay 007 25-Nov-13 20:53pm View    
Why are you so adamant. If you are a master than download the binary file from
and try it yourself. Let me also know what different you are doing.
1st value is "Mike Tyson", 2nd value is "1234567890", 3rd value is "1000.50" and last value is "Mike Tyson"
Akshay 007 25-Nov-13 3:50am View    
There are some applications that are made keeping Linux in mind, and these applications use binary format as their input. I don't think you are concentrating on the part where I say while writing the binary file the access mode set is sequential. It is similar to the access="SEQUENTIAL" in Fortran.
I will be using Binary Writer to write the output of my tasks, but it has to be in the same format as is the reader.
Akshay 007 25-Nov-13 2:47am View    
Hi Sergey,

To make things clear I am not using BinaryWriter to create the binary file. As said earlier the file is created on linux with another tool. The method of access is used as sequential for both reading and writing. My task here involves that I need to read that binary file in C# and use these values for further tasks and write the output to another binary file.

The length of my binary file is 40 as per br.BaseStream.Length, the string that is present in the binary file is "Akshay" and was initialized for 30 characters space. The float value inserted is "1000.50" and the int value inserted is "1234567890". All the 3 values are written in same line with tab delimited. When I read it using BinaryReader and as you mentioned about reading the values, I used ReadChars(30) for reading the string of 30 characters, then I used ReadSingle() as an alternative for float as both represent 4 byte floating value, and laslty I used ReadInt32(() as ReadInt64() will go beyond the stream length.

Foll is my code for reading
using (var br = new BinaryReader(new FileStream(filename, FileMode.Open, FileAccess.Read, FileShare.Read, 0x10000, FileOptions.SequentialScan)))
long pos, length;
length = br.BaseStream.Length;
pos = br.BaseStream.Position;

char[] name = br.ReadChars(30);
pos = br.BaseStream.Position;

float fVal = br.ReadSingle();
pos = br.BaseStream.Position;

Int64 intVal = br.ReadInt64();
pos = br.BaseStream.Position;

Please help me in understanding where I am making the mistake.