Comments by Rebics Copy

Rebics Copy 23-Nov-22 4:43am View

Did not understand new to this please tell me clearly.

Rebics Copy 11-Nov-22 4:00am View

Bro I am just learning and at this time i just want data in phpmyadmin that's it.
the error is undefined array key "email".

 <input type="password" name="password" class="form-control form-control-lg" required/>

and this is the code please let drag out me from this. frustated

Rebics Copy 11-Nov-22 3:54am View

Email

 <input type="password" name="password" class="form-control form-control-lg" required/>

this is the code in index.php

Rebics Copy 11-Nov-22 3:30am View

Deleted

ghh

Rebics Copy 11-Nov-22 3:29am View

Deleted

I know this but all this giving error of Fatal error: uncaught mysqli_SQL_exception: you

Rebics Copy 9-Nov-22 6:35am View

code is:

$sql= $conn->prepare("INSERT INTO form (first_name, last_name, mother_name, father_name, address) Values(?,?,?,?,?)");
$sql->bind_param("sssss", $fname,$Lname, $Mname, $fathername, $address);
Now giving thsi error:

Fatal error: Uncaught TypeError: mysqli::query(): Argument #1 ($query) must be of type string, mysqli_stmt given in C:\xampp\htdocs\demo\form\process.php:24 Stack trace: #0 C:\xampp\htdocs\demo\form\process.php(24): mysqli->query(Object(mysqli_stmt)) #1 {main} thrown in C:\xampp\htdocs\demo\form\process.php on line 24

Rebics Copy 9-Nov-22 6:34am View

code is:

$sql= $conn->prepare("INSERT INTO form (first_name, last_name, mother_name, father_name, address) Values(?,?,?,?,?)");
$sql->bind_param("sssss", $fname,$Lname, $Mname, $fathername, $address);
Now giving thsi error:

Fatal error: Uncaught TypeError: mysqli::query(): Argument #1 ($query) must be of type string, mysqli_stmt given in C:\xampp\htdocs\demo\form\process.php:24 Stack trace: #0 C:\xampp\htdocs\demo\form\process.php(24): mysqli->query(Object(mysqli_stmt)) #1 {main} thrown in C:\xampp\htdocs\demo\form\process.php on line 24

Rebics Copy 9-Nov-22 6:33am View

now giving this error:
Fatal error: Uncaught TypeError: mysqli::query(): Argument #1 ($query) must be of type string, mysqli_stmt given in C:\xampp\htdocs\demo\form\process.php:24 Stack trace: #0 C:\xampp\htdocs\demo\form\process.php(24): mysqli->query(Object(mysqli_stmt)) #1 {main} thrown in C:\xampp\htdocs\demo\form\process.php on line 24

Rebics Copy 9-Nov-22 4:06am View

did not work i tried f***ing solution that are there.....

Rebics Copy 9-Nov-22 4:01am View

I swear I am frustrated to finding the solution

Rebics Copy 9-Nov-22 3:59am View

prepare("INSERT INTO form (first_name, last_name, mother_name, father_name, address) Values(s,s,s,s,s)");
$sql->bind_param("sssss", $fname,$Lname, $Mname, $fathername, $address);

if ($conn->query ($sql) == TRUE) {
echo "New record created successfully";
} else {
echo "Error: " . $sql . "" . $conn->error;
}
$sql->close();
$conn->close();

?>

error:
Fatal error: Uncaught mysqli_sql_exception: Unknown column 's' in 'field list' in C:\xampp\htdocs\demo\form\process.php:20 Stack trace: #0 C:\xampp\htdocs\demo\form\process.php(20): mysqli->prepare('INSERT INTO for...') #1 {main} thrown in C:\xampp\htdocs\demo\form\process.php on line 20

and there is no mistake

Comments by Rebics Copy (Top 11 by date)