Comments by SACC92 (Top 1 by date)

I would need to convert very large numbers, of order 10^18, but your suggestion is actually helpful, as I was thinking the other way around, as in, take base b, then solve the equation, in this example, 2*b^6 + 3*b^5 + 7*b^4 + ... + 2 = 16947800. Your approach, as in doing it the other way around, seems far more effective. Do you think doing a search for the base with some sort of bisection algorithm for the base interval would work for large numbers as the ones I'll need to work with?