Comments by Member 13784265

Member 13784265 15-Oct-20 5:17am View

i get that but would it help me in displaying the jquery mobile dialoug box ?

Member 13784265 28-Aug-18 11:43am View

"unit test" and "native" works the same way ?

Member 13784265 28-Aug-18 11:36am View

what's the difference between managed and native unit testing ?

Member 13784265 21-Jun-18 9:20am View

thanks sir.
i am using visual studio and i am having this program on this compiler. but when i run this same program it run properly on Cfree.why is that so ?

Member 13784265 15-May-18 10:42am View

i tried this.it's working on cfree compiler but when i switch to Visual Studio, Visual Studio give errors.
ERRORS:
no operator ">>"matches these operands at line 22.
no operator "<<"matches these operands at line 43.

#include<iostream>
#include<fstream>
#include<conio.h>

using namespace std;

struct node
{
string name;
node *next;
};

int main()
{
node *head = NULL;
node *tail;
ifstream fin;
fin.open("naeem.txt");
string info;
while (!fin.eof())
{
fin >> info;
node *temp = new node;
temp->next = NULL;
if (!head)
{
temp->name = info;
tail = head = temp;
}
else
{
temp->name = info;
tail->next = temp;
tail = temp;
}
}

node *t = head;
int count = 1;

while (t != NULL)
{
cout << "[" << count << "]=>" << t->name << endl;
t = t->next;
count++;
}
_getch();
}

Member 13784265 15-May-18 10:35am View

i tried this.it's working on cfree compiler but when i switch to Visual Studio, Visual Studio give errors.
ERRORS:
no operator ">>"matches these operands at line 22.
no operator "<<"matches these operands at line 43.

#include<iostream>
#include<fstream>
#include<conio.h>

using namespace std;

struct node
{
string name;
node *next;
};

int main()
{
node *head = NULL;
node *tail;
ifstream fin;
fin.open("naeem.txt");
string info;
while (!fin.eof())
{
fin >> info;
node *temp = new node;
temp->next = NULL;
if (!head)
{
temp->name = info;
tail = head = temp;
}
else
{
temp->name = info;
tail->next = temp;
tail = temp;
}
}

node *t = head;
int count = 1;

while (t != NULL)
{
cout << "[" << count << "]=>" << t->name << endl;
t = t->next;
count++;
}
_getch();
}

Member 13784265 25-Apr-18 12:31pm View

thanks :)

Member 13784265 25-Apr-18 10:14am View

how can i check the frequency of each word in a string using the same technique ?

Member 13784265 24-Apr-18 12:02pm View

it doesn't on my compiler.i'm using the same input as you did but it keeps asking for input

Member 13784265 17-Apr-18 12:07pm View

is there anything i could do with my code that will reduce its time that it takes to run the whole program?

Member 13784265 17-Apr-18 11:24am View

i didn't get your question,sorry.

Member 13784265 17-Apr-18 11:17am View

at the end of the program i cout the time again to check the difference between start time and end time

Comments by Member 13784265 (Top 12 by date)