Comments by Anupkumar_vj (Top 17 by date)

yes..it compiles on Codeblock compiler

I have gone through your give link. Still I didn't get unwinding the recursion the current value of static variable.

i++*i++ means 3++*3++=3*3=9, i has incremented to 5. Now ++i*++i means ++5*++5=6*7=42 know ?

No..In codeeblock I am getting 9 and 49.

You have given slight mathematical idea..
I used my own idea like this
#include <stdio.h>
#include <stdlib.h>

int main()
{
int i,j;
for(i=1,j=100/50;i<21;i++,j=j+2)
{
printf("%d",((i-1)-(i-1)/10*(j-22)));
}
return 0;
}
Will it satisfy rules ? yes, its giving output in codeblock comipler..

You have given slight mathematical idea..
I used my own idea like this
#include <stdio.h>
#include <stdlib.h>

int main()
{
int i,j;
for(i=1,j=100/50;i<21;i++,j=j+2)
{
printf("%d",((i-1)-(i-1)/10*(j-22)));
}
return 0;
}
Will it satisfy rules ? yes, its giving output in codeblock comipler..

You have given slight mathematical idea..
I used my own idea like this
#include <stdio.h>
#include <stdlib.h>

int main()
{
int i,j;
for(i=1,j=100/50;i<21;i++,j=j+2)
{
printf("%d",((i-1)-(i-1)/10*(j-22)));
}
return 0;
}
Will it satisfy rules ? yes, its giving output in codeblock comipler..

You have given slight mathematical idea..
I used my own idea like this
#include <stdio.h>
#include <stdlib.h>

int main()
{
int i,j;
for(i=1,j=100/50;i<21;i++,j=j+2)
{
printf("%d",((i-1)-(i-1)/10*(j-22)));
}
return 0;
}
Will it satisfy rules ? yes, its giving output in codeblock..

I think printf returns 21 but output should have 20 in numbers.

There I can't add another loop bcz it violates specified rule.

Yea. I learnt for loop. But only one loop should be used

Its was asked in job interview, finding solution but not getting. I want answer for next some other interview