Comments by Waqar (Vicky) (Top 11 by date)

i am able to solve my problem with
List<KeyValuePair<string, string>>
it was my first time to put my question on this platform for help
well learn too many things/
Next time i will make my question more clear
Thanks

i am able to solve my problem with
List<KeyValuePair<string, string>>
it was my first time to put my question on this platform for help
well learn too many things/
Next time i will make my question more clear
Thanks

i am able to solve my problem with
List<KeyValuePair<string, string>>
it was my first time to put my question on this platform for help
well learn too many things/
Next time i will make my question more clear
Thanks

Yup exactly you got my pint i was talking about this.
Thanks.

Thanks for you reply @Dave Kreskowiak

actually i am doing here to read first two lines of csv
and then add them both in my data table columns collection.

I have to add both column names like (Name,Father Name,Age) and Column values Like(Adam,Yann,32) both in the collection.
here is my code given below.
.
var data = new Dictionary<string, string>();
var columnHeaders = headerLine.Split(',');
var dataValues = dataLine.Split(',');

for (var i = 0; i < columnHeaders.Count(); i++)
{
data.Add(columnHeaders[i], dataValues[i]);
}
foreach (var pair in data)
{
CurrentRecord.MappingResourceValues.Add(new DataModels.Tables.MappingResourceValue(0, null, pair.Key, pair.Value, 0, CurrentRecord.Id));
}

Thanks for you reply @PIEBALDconsult
If i use Disctionary<int,string>
then i have to add both column names like (Name,Father Name,Age) and Column values Like(Adam,Yann,32) both in the collection.
here is my code given below.
.
var data = new Dictionary<string, string>();
var columnHeaders = headerLine.Split(',');
var dataValues = dataLine.Split(',');

for (var i = 0; i < columnHeaders.Count(); i++)
{
data.Add(columnHeaders[i], dataValues[i]);
}
foreach (var pair in data)
{
CurrentRecord.MappingResourceValues.Add(new DataModels.Tables.MappingResourceValue(0, null, pair.Key, pair.Value, 0, CurrentRecord.Id));
}