Comments by Member 11373970 (Top 25 by date)

Thanks for your response Karthik..!
I will take care of conversion to/from JSON....just need values for each parameter of a class in json format(in text file) like mentioned above..!

Yes Karthik..I know that..!
But,for demo purpose to the client need some values in JSON format.

Same provided above.
For Screenshot: https://snag.gy/gPxpWK.jpg

PFB...!

Class A --> a,b,c,d,e,f
Class B --> g,h,i,j
Clacc C --> k,l,m,n

Sample Values:
a --> 5,8,10,12
b --> 2,4,3.5,6
c --> 4,2,3,5
d --> 200,620,401,124
e --> 5,10.1,15
f --> True/false

g --> 10,55,120,69
h --> 15,2.65,7.5,9
i --> 600,1.5,2,8
j --> 5,8,16,55

k --> 5,16,18,12
l --> 10.1,5,15,85
m --> 13,21,9,75
n --> 5,75,20,1

I'll get these values programmatically from Hardware Kit..!
But, for this time being Input is JSON file with all values..!

Need to add 3 more values for each parameter of a class in above mentioned format..!

Not code am looking for..!
It should be in JSON format like below.

var obj = {
"A": {
"a": { "Current": 30.0},
"b": { "Current": 60.0},
"c": { "Current": 60.0},
"d": { "Current": 60.0},
"e": { "Current": 60.0},
"f": false
},
"B": {
"g": { "Current": 30.0},
"h": { "Current": 60.0},
"i": { "Current": 60.0},
"j": { "Current": 60.0},
},
"C": {
"k": { "Current": 30.0},
"l": { "Current": 60.0},
"m": { "Current": 60.0},
"n": { "Current": 60.0},
}
}

Above one for 1 value...in the same way need 4 values for each parameter of a class in JSON format..!

Sure..!
Need .json file with all values, as mentioned earlier..!

Exactly Karthikk..!

It will be done like below..!

JObject o1 = JObject.Parse(File.ReadAllText(@"c:\videogames.json"));

// read JSON directly from a file
using (StreamReader file = File.OpenText(@"c:\videogames.json"))
using (JsonTextReader reader = new JsonTextReader(file))
{
JObject o2 = (JObject)JToken.ReadFrom(reader);
}

Accordingly,need .json file with all values, as mentioned earlier..!

Great Karthik..!
But, am expecting text file with the values in JSON structure/format..!

Yes Karthik..!

Yes..!

3 classes namely A, B and C.
Each class having different parameters, i.e, A-->a,b,c,d,e,f, B--> g,h,i,j and C--> k,l,m,n...!
Each parameter having 4 values.. i.e., a.value--> 10, 45, 85,1 and b.value --> 4,55,98,4.(In JSON format).

Hope you understand..!

Need four current values of each parameter and that should be in JSON format to display as four rows in grid.

The above one was with 1 current value..!

That's fine Karthik.
The above one was fine for 1st row.
How to add the values of 4 rows (in JSON text file) in best way..!

I will take care of the logic to read the data from JSON file and display the same in my grid.
But, my question is..the data should be in JSON structure..!

Thanks Karthik for your response..!
https://snag.gy/8MGxLn.jpg (For Screenshot)

Displays only current values of each parameter and it was not required to mention Min, Max and default vales.
Instead it should be only with current values like below.

var obj = {
"A": {
"a": { "Current": 30.0},
"b": { "Current": 60.0},
"c": { "Current": 60.0},
"d": { "Current": 60.0},
"e": { "Current": 60.0},
"f": false
},
"B": {
"g": { "Current": 30.0},
"h": { "Current": 60.0},
"i": { "Current": 60.0},
"j": { "Current": 60.0},
},
"C": {
"k": { "Current": 30.0},
"l": { "Current": 60.0},
"m": { "Current": 60.0},
"n": { "Current": 60.0},
}
}

Please suggest me the best way..!

It should be like this in grid format as 1st and 2nd row.(Unable to attach screenshot here)
5 2 4 200 50 10 1 600 5 51 50 1

8 4 2 620 10 55 2 150 8 16 25 0

Displays only current value of each parameter..!
Provided by you is for one row..!