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Why do you think a lock is necessary here? Lock is necessary when accessing finite resources such as a file where you need to ensure only one thread updates it a time. With the textbox you only need to use the Invoke method it you are trying to update it from a thread other than the UI thread.
I know the language. I've read a book. - _Madmatt
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Um, coming from C++, I would have thought calling a function from two different threads might cause some re-entrancy issues when working on a common resource (the TextBox's content they both try to update). I would have expected the output to be either interleaved ("AAAA" and "BBBB" resulting in "AABABBBA" for example) in the better case, or some variable corruption in the worse case.
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Yes, the original code is thread-safe. This is how it works:
- thread 1 calls the method containing your snippet, I'll call it SetText();
- it detects invoke is required, launches a windows message to the GUI thread, and waits for it to return;
- the GUI thread now executes the same method SetText(), sees no invoke is required, sets the TextBox property, and returns;
- this causes thread 1, still waiting inside its SetText(), to continue.
Now everything the GUI thread does gets sequenced (well, not absolutely aacurate, but good enough here) through its event queue, so even if another thread (thread 2) were to call SetText, it would basically execute the same steps as listed above, and the common part, executed on the GUI thread, would be sequenced by the event queue.
So any number of SetText() calls will execute in the order they get called, without them interfering amongst themselves.
Adding a lock does not make it any safer; and as you discovered, if it covers the entire content of SetText(), it brings everything to a halt, as the basic concept of the construct is that SetText, when called on a thread other than the GUI thread, causes itself to be executed once more, on the GUI thread, which would be prevented by the very lock you added.
Luc Pattyn [Forum Guidelines] [Why QA sucks] [My Articles]
I only read formatted code with indentation, so please use PRE tags for code snippets.
I'm not participating in frackin' Q&A, so if you want my opinion, ask away in a real forum (or on my profile page).
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Hi, thanks for the answer... good to know about the queue
I think you confused the SetText (aka the snippet) thing though. Unless C# does something behind my back (not that I'd be surprised  but I guess it would require the CLR to detect the caller of the Invoke method and recall it, and on top of that, it would render the delegate parameter useless), SetText doesn't get called again, so the deadlock is not due to the SetText method recursively calling itself in another thread (in fact, the deadlock only happened in certain cases and required a lot of tries to replicate in each of those cases).
In other words, "as the basic concept of the construct is that SetText, when called on a thread other than the GUI thread, causes itself to be executed once more, on the GUI thread" seems wrong to me Just going over it here so that I know I'm not mistaken...
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Sorry, my reply wasn't very accurate; I should have payed more attention to the details of your code. The way I do such things typically is like so:
public void SetText(Control control, string text) {
if (control.InvokeRequired) {
control.Invoke(new ControlStringConsumer(SetText), new object[]{control, text});
} else {
control.Text=text;
}
}
and then my earlier reply would apply. My "canonical form" as I call it here[^], has the advantage of containing the actual operation code only once.
Your code, which was
if (this.OutputConsole.InvokeRequired) {
this.OutputConsole.Invoke(
new OutputConsoleUpdater(delegate(string s) { this.OutputConsole.AppendText(s + "\r\n"); }),
text);
} else {
this.OutputConsole.AppendText(text + "\r\n");
}
could be simplified to
this.OutputConsole.Invoke(
new OutputConsoleUpdater(delegate(string s) { this.OutputConsole.AppendText(s + "\r\n"); }),
text);
assuming we are NOT on the GUI thread. Using Invoke() it also causes the delegate to be executed on the GUI thread, through Windows messages, implying an automatic sequential treatment.
Now I'm not sure about the lock issue you raised; it may depend on where exactly you put it, and even more on what is inside the OutputConsoleUpdater constructor. But anyway, the conclusion will be there is no need for such a lock.
FWIW: you could break the automatic sequencing by using Application.DoEvents() inside some event handler; that is exactly why doing so is a very bad idea most of the time.
Luc Pattyn [Forum Guidelines] [Why QA sucks] [My Articles]
I only read formatted code with indentation, so please use PRE tags for code snippets.
I'm not participating in frackin' Q&A, so if you want my opinion, ask away in a real forum (or on my profile page).
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Perfect, the idiom you use is definitely more elegant  glad I learned something new today.
As for the deadlock, I'm quite sure why it happens (the "pump" that does the Invoke requests doesn't get called as the whole thread is stuck waiting in the first place), no problems there.
thanks a lot for your time! 
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hello.
i am creating a jpeg encoder i need to access a image file.
can u tell me how can i read and write using dll.
getPixel(), setPixel() is very slow.
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Is there a reason you can't use:
Bitmap RawImage = new Bitmap(Filename);
Once it's in the Bitmap, then you can use the pixel buffer for faster access. Google will help with how to do that.
CQ de W5ALT
Walt Fair, Jr., P. E.
Comport Computing
Specializing in Technical Engineering Software
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I have the following classes in Java which i want to convert to C# but have errors with the undelined codes. (Can someone help me with the C# equivalent of PUT and GET)
class TagInfo{
public int tagOffset;
public int tagLength;
public TagInfo(){
}
}
private void buildMetaData()
{
Record record = getData();
int offset = IMGREC_TAGLIST_INDEX;
int numTags = 0 ;
short tagID = 0;
try
{
numTags = this.getNumberOfTags() ;
for (int i=0; i < numTags; i++){
TagInfo info = new TagInfo();
info.tagOffset = offset;
info.tagLength = TagRecord.TAG_DATA_INDEX + record.readInt(offset + TagRecord.TAG_DATALEN_INDEX);
tagID = record.readShort(offset + TagRecord.TAG_ID_INDEX);
offset += info.tagLength;
tagInfo.put(new Short(tagID),info);
Console.WriteLine("tagID = " + tagID);
}
}
catch (Exception ex)
{
}
finally
{
}
this.imageOffset = offset;
this.imageSize = record.getLength() - offset;
}
public TagRecord getTagByID(short id)
{
TagRecord record = null;
TagInfo info = (ImageRecord.TagInfo)tagInfo.get(new Short(id));
if (info != null){
byte[] data = this.getData().read(info.tagOffset,info.tagLength);
record = new TagRecord(data);
}
return record;
}
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Those lines appear to be using a variable which does not exist. What is the type of tagInfo and where does it come from? It isn't a local variable or parameter or even a field in the class - so what is it?
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This might not be quite right as you did not post the entier code, but the following should help you. Note the dictionary declaration and add/get code. I have used a generic dictionary to enable strong typing.
class TagInfo{
public int tagOffset;
public int tagLength;
public TagInfo(){
}
}
System.Collections.Generic.Dictionary<int, TagInfo>; TagInfoDictionary = new System.Collections.Generic.Dictionary<int, TagInfo>();
private void buildMetaData()
{
Record record = getData();
int offset = IMGREC_TAGLIST_INDEX;
int numTags = 0 ;
short tagID = 0;
try
{
numTags = this.getNumberOfTags() ;
for (int i=0; i < numTags; i++){
TagInfo info = new TagInfo();
info.tagOffset = offset;
info.tagLength = TagRecord.TAG_DATA_INDEX + record.readInt(offset + TagRecord.TAG_DATALEN_INDEX);
tagID = record.readShort(offset + TagRecord.TAG_ID_INDEX);
offset += info.tagLength;
this.TagInfoDictionary.Add(tagID, info);
Console.WriteLine("tagID = " + tagID);
}
}catch (Exception ex){}
finally{}
this.imageOffset = offset;
this.imageSize = record.getLength() - offset;
}
public TagRecord getTagByID(short id)
{
TagRecord record = null;
TagInfo info = this.TagInfoDictionary[id];
if (info != null){
byte[] data = this.getData().read(info.tagOffset,info.tagLength);
record = new TagRecord(data);
}
return record;
}
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hi
what is the equivalent of this code in c#
this code is in VB6
Chr$(Asc("0")
thanks
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Try Convert.ToChar(6);.
The output is a unicode value.
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Apart from lacking a parenthesis, it does not make much sense; Asc() returns a number holding the ASCII value, which is 48 for a zero; and Chr$() does the inverse, it returns the ASCII character equivalent of a numeric value. So they cancel each other, it simply means "0"
In C# we use different delimiters for string literals and character literals, so you may want a simple '0'
Luc Pattyn [Forum Guidelines] [Why QA sucks] [My Articles]
I only read formatted code with indentation, so please use PRE tags for code snippets.
I'm not participating in frackin' Q&A, so if you want my opinion, ask away in a real forum (or on my profile page).
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i want convert eny caractere in ascii the 0 is a exemple
so if there is some code to calc ascci please send it to me
i need it now
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in .NET an ASCII character is just a character, the first 128 Unicode characters ARE the ASCII characters.
So
'a'
"a"[0]
(char)97
are all the same lower-case a, as they are
a character literal
the way to get the first character of a string
a number cast to a character
If you don't understand the fundamentals, go buy a book and study it. If you have an overall problem, tell us about the problem rather than asking a detail question on what probably isn't even the right detail.
Luc Pattyn [Forum Guidelines] [Why QA sucks] [My Articles]
I only read formatted code with indentation, so please use PRE tags for code snippets.
I'm not participating in frackin' Q&A, so if you want my opinion, ask away in a real forum (or on my profile page).
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There is no equivalent; C# developers are smart enought not to write anything as silly as that. 
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thank you it's like that when sharing information has a beginning researcher in c #
thank you very much
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Sure, however you should allow some slack for VB coders trying to spit out some C#.
How about
char ascee='0';
char uniquode=Encoding.UTF8.GetChars(Encoding.ASCII.GetBytes(new char[]{ascee}))[0];
Luc Pattyn [Forum Guidelines] [Why QA sucks] [My Articles]
I only read formatted code with indentation, so please use PRE tags for code snippets.
I'm not participating in frackin' Q&A, so if you want my opinion, ask away in a real forum (or on my profile page).
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the out result is the same of first value of ascee no chage ???
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Luc Pattyn wrote: allow some slack for VB coders
They made their sty they can wallow in it.
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sig material it is.
Luc Pattyn [Forum Guidelines] [Why QA sucks] [My Articles]
I only read formatted code with indentation, so please use PRE tags for code snippets.
I'm not participating in frackin' Q&A, so if you want my opinion, ask away in a real forum (or on my profile page).
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Hi everybody. ...It's been way too long since I've had to issue a production release, but guess what I get to do this week lol
..at any rate, I'm writing up the installme.doc checklist for Production Management to be able to roll our code out to production, and I ran into something that I'm curious to know everyone's thoughts on:
1)Are there any tangible benefits to issuing a true "Release" build to production?
2)Or does it suffice to merely build in "Debug" and not copy over the pdb file that is generated with it?
3)Are they equivalent processes and issuing a "Release" build is merely more explicit in stating "This is built for a production release?"
(Our current SOP is #2)
Thoughts, opinions (other than a mere msdn reference...I'm requesting information from real world experience with the two methods)
"I need build Skynet. Plz send code"
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That depends on your configuration -- usually a release build will use optimizations and the debug doesn't,
and the debug build will include debug symbols and the release doesn't,
so the release version may be quicker and/or more efficient than the debug version.
But you can configure things in other ways if you want.
I have no idea what PDB files do, I wish the compiler wouldn't create them at all, I just delete them and I have no trouble.
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