|
I made it with a Gridview (and an imagefield) instead of DataGrid.
...
dataimageurlfield="ID"
dataimageurlformatstring="loadImage.aspx?MyId={0}"
...
The loadImage (with code-behind) takes the ID and calls a method, which gives several strings
and the picture-bytearray in return.
-- modified at 7:09 Friday 12th January, 2007
|
|
|
|
|
i develop some reports using crystal report and when i run the report in ie browser,it get all of data in one page but when i print the report it print in alot of page and the page header visiable in first page.
i want to visiable the page header in all page
thanks
|
|
|
|
|
I haven't used crystal in a long time but if I remember correctly the only thing you can do is render a pdf to client and the user print that. The html version never prints just right.
|
|
|
|
|
Hi,
I have an value bound to a column in a datagrid. I need to pass that value to a function. I thought this would easy for me.
I used something like:
Dim e As DataGridItem<br />
ds = obj.getDetails(e.Cells(0).Text)
This would mean that it is trying to extract as a string OR convert the contents of the cell to string. I need the value to be extracted as an integer. Char to Integer conversions cannot happen.
Please advise me if you can. Is there a straighforward way to extract the value of that cell?? Thank you.
-- modified at 9:52 Wednesday 10th January, 2007
|
|
|
|
|
The table cell contains a string value, not a number. If you want the value as a number, you have to parse the string.
If the value in the table cell comes from a numeric field in the data source, you have to read the value from the data source instead of from the table cell to get it in the original numeric form. When the value is put in the table cell it's convertered into a string value.
---
Year happy = new Year(2007);
|
|
|
|
|
Thank you for the reply mate. Very useful info! 
|
|
|
|
|
I'm having an error message sounding like :
Prepared statement '(@id text)SELECT * from isp_email.staff where @id like +txtname.' expects parameter @id, which was not supplied.
This message appear when I press button to select a row at run time. What could be the problem?
SqlCommand myCommand = new SqlCommand();
myCommand.Connection=con;
myCommand.CommandText="SELECT * from isp_email.staff where @id like +txtname.Text";
SqlParameter myparam = new SqlParameter("@id",SqlDbType.Text);
myparam.Value=ID;
myCommand.Parameters.Add(myparam);
SqlDataAdapter myAdapter=new SqlDataAdapter(myCommand);
DataSet ds = new DataSet();
myAdapter.Fill(ds);
con.Open();
myCommand.ExecuteNonQuery();
dgupdate.DataSource=ds;
dgupdate.DataBind();
con.Close();
Thank you.
|
|
|
|
|
Try this instead. Also you should attempt to use stored procedures whenever possible.
myCommand.CommandText="SELECT * from isp_email.staff where @id like '" + txtname.Text + "'";
only two letters away from being an asset
|
|
|
|
|
It does not give any change still get the same error. Do you think there can there is any difference? Because I never use them but looks like it works.
Thank you very much.
|
|
|
|
|
Sorry missed something, try this
myCommand.CommandText="SELECT * from isp_email.staff where id = @id and name like '" + txtname.Text + "'";
Assuming id and name are the names of the columns in the database
only two letters away from being an asset
|
|
|
|
|
Actually you shouldn't try this, because the query would be vulnerable to a SQL Injection. Instead do it like this:
myCommand.CommandText="SELECT * from isp_email.staff where id = @id and name like '%' + @name + '%'";
myCommand.Parameters.Add("@name", txtname.Text);
|
|
|
|
|
I think in place @id, he need to give the column name and there exactly he may be doing wrong.
Best Regards,
Apurva Kaushal
|
|
|
|
|
Still no different. but I've tried this "SELECT * from isp_email.staff where fullname=@fullname and fullname Like %'"+txtname.Text+"'%"; and the error was like:Incorrect syntax near 'Ndayahundwa,Claude'. could I be on the write truck?
|
|
|
|
|
Continue in the same thread instead of starting a new.
You are still trying to use an ASP.NET control from the database. I already explained that the database can not use it.
---
Year happy = new Year(2007);
|
|
|
|
|
Thanks What do you mean by running thread? If you could be more specific please because I'm afraid I'm not getting what exactly you are trying to advise me
Thank you.
|
|
|
|
|
What exactly he wanted to say is you have earlier also posted the same question in this forum so inspite of creating a new forum continue that thread only.
Best Regards,
Apurva Kaushal
|
|
|
|
|
Hi Friends,
I have developed some crystal reports on my development machine everything is working fine.
But when i deployed them on server where we haven't got visual studio and crystal reports installed.
it gives error.
that is assembly refrence for CrystalDecion framework not found.
there is not any DLL file for crystal framework its in GAC so can any one tell me .
Whats the best way to deploy Crystal reports with a web solution.?
thanks
Naveed Kamboh
|
|
|
|
|
hi frind,
the best way you must create setup packg for your site and it will include the crystall report dll's in the packg.
|
|
|
|
|
Hi,
I got the following error when i am trying to bind data to grid dynamicaly.
DataBinding: 'System.Data.DataRowView' does not contain a property with the name
|
|
|
|
|
Not a diffcult one to debug. The datasource appears to not have a column with the name the datagrid column is bound to.
only two letters away from being an asset
|
|
|
|
|
The name of the Field in the Item Templates where you are not binding the data is not presnt in the database or selection list.
|
|
|
|
|
Hi, i have created a forum which is about trading. Now, the only problem i have is how to check who is logged in? I want to show the users which users are logged in??
Regards,
Adrian
Adrian De Battista: .Net Programmer, Java Programmer and Web Designer.
|
|
|
|
|
ADY007 wrote: Hi, i have created a forum which is about trading.
That's nice. Now, do you have specific question? What are you using? What have you tried? There aren't many mind readers here so you have to explain a little bit more.
only two letters away from being an asset
|
|
|
|
|
So, I am using asp.net with vb.net. When they register they are creating another row in the Members database automatically.
Now when they login, I need to know how to log all the sessions from different users and put them on the page.
Adrian De Battista: .Net Programmer, Java Programmer and Web Designer.
|
|
|
|
|
Create an application variable that will hold the names (and other info if necessary) of users who log in successfully, then use it to display. Of course you also need to handle logouts and abandoned sessions.
only two letters away from being an asset
|
|
|
|
General 
News 
Suggestion 
Question 
Bug 
Answer 
Joke 
Praise 
Rant 
Admin 
Submit an article or tip
