C / C++ / MFC

B bobj (aobj);
B* bbptr = new B (bobj);

#include "myDummyFile.h"

struct MyStruct
{
  const char* s;
  int i;
  void* ptr;
};


class MyClass
{
public:
  MyClass ();
  void MyMehod1 (const std::vector<int>& v) {};
  void MyMethod2 (const MyStruct& s) {};
};

int main()
{

  MyClass c;
  c.MyMehod1 ({ 0, 1, 2, 3 });
  c.MyMethod2 ({ "", 0, nullptr });
}

MyClass.MyMethod1(new byte[]{0, 1, 2, 3}); 

arnold_w wrote:

I try to keep my ARM-code as close to pure C

arnold_w wrote:

I plan to work on this first thing in the morning.

void Function(const std::vector<uint8_t>& values)

Function(std::vector<uint8_t>{ 5, 4, 3});

Joe Woodbury wrote:

void Function(const std::vector<uint8_t>& values)

void Function(uint8_t* values)

void Function(uint8_t* values, unsigned long int size); //normal C function implemented elsewhere
void Function(const std::vector<uint8_t>& values) {
    Function(values.data(), values.size());
}
int main() {
    Function({1, 2, 3});
    return 0;
}

uint16_t getUint16Value(int someParameter) {
    // Unimportant implementation
}

void myFunction() {
    uint16_t destArray[2];
    memcpy(destArray, (uint16_t[2]){getUint16Value(0), getUint16Value(1)}, sizeof(uint16_t[2]));
}

Quote:

You should call this function from a background thread. Failure to do so could cause the UI to stop responding.

Richard Andrew x64 wrote:

I ask because I do not want the application to terminate when the secondary thread terminates. My understanding of the docs is that that could happen if I use a UI thread.

ThreadA->ThreadB_DoSomething();
ThreadB->ThreadA_Dosomething();