Click here to Skip to main content
15,915,319 members
Please Sign up or sign in to vote.
1.00/5 (1 vote)
i have a table like


id status statusid complaintto
1 open 14 employee
1 pending 15 administration
1 closed 16 xyz
2 open 14 employe
2 pending 15 administration
2 closed 16 xyz
3 open 14 employe
3 pending 15 administration
3 pending 15 xyz


i don't want to show id closed

3rd id record will be shown

thankx
Posted

try this:
exclude the id which are having closed status and then select the rest
you can use self joins too.
SQL
SELECT * FROM [Sample] where id not in
(
    SELECT id from [sample] where statusid = 16 -- for closed
)
 
Share this answer
 
v2
Comments
Parazival 28-Feb-15 1:25am    
my 5+ niceeeee answer awesome.............

i got the answer

thanks friend
Schatak 28-Feb-15 2:56am    
Good, then accept the solution :P
Parazival 28-Feb-15 6:57am    
where can i dowload the xml full material

thankx
Schatak 2-Mar-15 23:58pm    
which xml?
Not Clear but,If you don't want to show the record with closed status,do like this,
SQL
SELECT id,status,statusid,complaintto from Table where status!='closed'


Or if you want to omit status,then just leave status from the query.
SQL
SELECT id,statusid,complaintto from Table where status!='closed'


Edit:2
You may get it from two way by using where clause.
SQL
select distinct a.id from #table1 as a inner join
 (select id,count(id) as Count1 from #Table1 where status!='closed' group by id) as b
  on a.id=b.id and b.Count1=3 

Or simply do like this,
select id from #table1 where statusid!=16 and ID=3 and status='pending' and complaintto='xyz'
 
Share this answer
 
v3
Comments
Parazival 28-Feb-15 0:30am    
it will show

id status statusid complaintto
1 open 14 employee
1 pending 15 administration
2 open 14 employe
2 pending 15 administration
3 open 14 employe
3 pending 15 administration
3 pending 15 xyz

but i want answer like

id
3
Parazival 28-Feb-15 0:33am    
i mean if any id(1,2,3) have (16)

that id should not show to me
Rajesh waran 28-Feb-15 1:21am    
I have updated my solution.Have a look.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)



CodeProject, 20 Bay Street, 11th Floor Toronto, Ontario, Canada M5J 2N8 +1 (416) 849-8900