How to open file explorer at given location in c#?

// required in addition to other 'using necessary
using System.Diagnostics;
using System.IO;

private void OpenFolder(string folderPath)
{
    if (Directory.Exists(folderPath))
    {
        ProcessStartInfo startInfo = new ProcessStartInfo
        {
            Arguments = folderPath,
            FileName = "explorer.exe";
        };

        Process.Start(startInfo);
    }
    else
    {
        MessageBox.Show(string.Format("{0} Directory does not exist!", folderPath));
    }
}

Note: if I was writing this in production code, I'd probably wrap the whole thing in a Try/Catch to intercept possible access permission errors.

you can try by executing run command as below

System.Diagnostics.Process process = new System.Diagnostics.Process();
System.Diagnostics.ProcessStartInfo startInfo = new System.Diagnostics.ProcessStartInfo();
startInfo.WindowStyle = System.Diagnostics.ProcessWindowStyle.Hidden;
startInfo.FileName = "cmd.exe";
string _path = "c:/windows";
startInfo.Arguments = string.Format("/C start {0}", _path);
process.StartInfo = startInfo;
process.Start();

The easy way is to ask Google. It take far less time to find the answer that way than to write the question itself here : https://www.google.ca/?gws_rd=ssl#q=open+file+in+explorer+c%23[^]

The question has been answered here : http://stackoverflow.com/questions/1073353/c-how-to-open-windows-explorer-windows-with-a-number-of-files-selected[^]

I think that you can open either a folder or select a file that way... but I'm not sure. For sure, I use it to open containing folder with initial selection in my application and it works quite well. I don't remember what I use but it should be very similar to what I have found using a search.

Update
To open a folder, you just specify folder name without /select, part. Something like explorer c:\folder_name.

/select option requires an existing file or folder and open its parent and select the item. Thus both options are available.