How do I query duplicate rows from sql database

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SQL-Server

I have this table
column1
1
0
2
4
5
1
8
2
6

How would I get a result like this with sql query
column1
1
1
2
2

Posted 31-Jan-14 3:44am

wizy@2020

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2 solutions

Solution 1

try this hope it will help you

SQL

SELECT
    column1, COUNT(column1)
FROM
    table_name
GROUP BY
    column1
HAVING
    COUNT(column1) > 1

Posted 31-Jan-14 3:52am

Salman622

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Malte Klena · Accepted Answer · 2014-01-31T03:54:00

Solution 2

DECLARE @table TABLE (column1 int)
INSERT INTO @table VALUES (1)
INSERT INTO @table VALUES (0)
INSERT INTO @table VALUES (2)
INSERT INTO @table VALUES (4)
INSERT INTO @table VALUES (5)
INSERT INTO @table VALUES (1)
INSERT INTO @table VALUES (8)
INSERT INTO @table VALUES (2)
INSERT INTO @table VALUES (6)

SELECT * 
FROM @table
WHERE column1 IN 
(
	SELECT t.column1
	FROM @table t
	GROUP BY column1
	HAVING COUNT(t.column1) > 1
)
ORDER BY 1

Posted 31-Jan-14 3:54am

Malte Klena

Comments

wizy@2020 31-Jan-14 10:41am

what if I have something like this
column1 column2
a 1
a 1
a 2
b 5
b 5
b 4
I want something like this
column1 column2
a 1
a 1
b 5
b 5

Malte Klena 31-Jan-14 12:45pm

DECLARE @table TABLE (column1 char(1), column2 int)
INSERT INTO @table VALUES ('a',1)
INSERT INTO @table VALUES ('a',1)
INSERT INTO @table VALUES ('a',2)
INSERT INTO @table VALUES ('b',5)
INSERT INTO @table VALUES ('b',5)
INSERT INTO @table VALUES ('b',4)

SELECT *
FROM @table
WHERE column2 IN
(
SELECT t.column2
FROM @table t
GROUP BY column2
HAVING COUNT(t.column2) > 1
)
ORDER BY 1