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I a table "person" and need a query for those personName who's

1.salary is maximum

2.cityCode is 12

3. age is 32



suppose- there are 3 person with name RAM .

AND 3 with name sunil

and 3 person with name rahul....


and i need the only those record who contain the maximum salary

means ram with maximum salary , sunil with maximum salary and rahul with maximum salary
Posted
Updated 9-Jul-13 19:31pm
v3

Try this

SQL
select  PersonName, MAX(Salary)
from    PERSON
where   cityCode = 12
and Age = 32
group by PersonName
 
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Comments
siddharth629 10-Jul-13 5:01am    
thanks sir.
This will require a multipart query. You need one part to find the maximum salary for a given citycode and age, and one part to return the name... like this:

SQL
select personName 
from person 
where salary = (select max(salary) from person where citycode = 12 and age = 32) 
and citycode = 12 
and age = 32
 
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Comments
Raja Sekhar S 10-Jul-13 1:16am    
Good one... +5..!
_Damian S_ 10-Jul-13 1:18am    
Two different solutions for the OP to choose from!!
Raja Sekhar S 10-Jul-13 1:28am    
Yep...
If you are asking for three queries....
SQL
Select top(1) PersonName from person Order by Salary Desc -- maximum salary
Select PersonName from person where citycode=12  -- CityCode=12
select PersonName from Person where age=32  -- age=32


if you are asking for name of the person earning highest salary in citycode 12 and age 32. Then the query is:
SQL
Select top(1) PersonName from person where citycode=12 and age=32 order by salary Desc
...

if this is not what u required.. use Improve Question widget....

As per your requirement u can use the multiQuery written by Damian S or
SQL
Select p1.PersonName from person p1 
inner join (Select Max(salary) as maxsalary from person where Citycode=12 and age=32)p2 on p1.salary=p2.maxsalary Where p1.CityCode=12 and p1.age=32


But if you want max salary grouped on person you can use:
SQL
Select PersonName, max(Salary) as Salary from person where age=32 and Citycode=12 Group by PersonName
 
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v5
Comments
_Damian S_ 10-Jul-13 1:12am    
Very nice solution using select top(1)... have a 5 on me!!
Raja Sekhar S 10-Jul-13 1:14am    
Thank You _Damian S_...

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