String Compression by Number of Characters

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HI,
I want to reduce the number of characters of a string of about 20 characters. How can it be possible.? What all possibilities are there.?
NOTE: I am not interested in its size. I just want it to be containing less number of characters and When it is uncompressed I should get back the original string.

Posted 23-Mar-13 21:10pm

Girish BS

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Girish BS · Answer 1 · 2013-03-25T04:09:00

Solution 3

The problem here is that the input string is not known but I only know its size i.e it has 20 characters. I want this solution for mobile activation for registration. So for this if the characters in the string can be reduced then it will be easy to text for the user. I think now the problem is clear.

Posted 25-Mar-13 4:09am

Girish BS

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Maciej Los 25-Mar-13 11:10am

This is not an answer. Plase, use "Have a question or comment" widget to related answer/solution or "Improve question" widget to update your question. Please, delete this solution.

Maciej Los 25-Mar-13 13:50pm

No, problem still is not clear. SMAZ algorithm is two-way. It can compress any string and decompress it:

int smaz_compress(char *in, int inlen, char *out, int outlen);
int smaz_decompress(char *in, int inlen, char *out, int outlen);

Maciej Los · Answer 2 · 2013-03-24T00:03:00

As Zoltan wrote, it's not so easy... especially when you do not provided enough information.

Some usefull examples, you'll find here:
A Simple String Compression Algorithm[^]
Easy String Compression and Encryption[^]

Interesting alternative is SMAZ[^] - simple compression library suitable for compressing very short strings. It works better with English and it's not general purpose for compressing string data.

You can always use zip, gzip, 7-zip (and other) libraries to compress/decompress data.

**Zoltán Zörgő** · Answer 3 · 2013-03-23T21:30:00

Solution 1

Compression in general is a little bit more complicated than that. But there is one, that might look like what you described, it is called run-length encoding[^].

Posted 23-Mar-13 21:30pm

Zoltán Zörgő

Comments

Maciej Los 24-Mar-13 6:05am

A 5! Pretty good answer for unclear question ;)

Zoltán Zörgő 24-Mar-13 14:57pm

Thank you!