Need explanation. Why print 6 4 instead of 6 8

Question

1.00/5 (1 vote)

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C++

int ray[5] = { 2, 4, 6, 8, 10 };
	int* p = ray;
	*p = ray[2];
	std:: cout <<  *p <<" "<< *(p + 1) << std::endl;

What I have tried:

I need an explanation of why it printed 6 4 instead of 6 8.

Posted 3-Nov-23 4:26am

Member 16131609

Updated 4-Nov-23 1:55am

Deeksha Shenoy

v2

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Comments

jeron1 3-Nov-23 10:35am

p starts out is a pointer to array (ray) index 0. You then set the contents of the memory that the pointer points to, to the contents of ray[2] which is 6. Your pointer p is still pointing to array index 0 at this point. You print the contents pointed to by p (array index 0) which is now 6, you increment p so it points to array index 1, which contains the value of 4.

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CPallini · Accepted Answer · 2023-11-03T05:36:00

Solution 2

Did you possibly mean

C++

int ray[5] = { 2, 4, 6, 8, 10 };
int* p = &ray[2];
std:: cout <<  *p <<" "<< *(p + 1) << std::endl;

?

Posted 3-Nov-23 5:36am

CPallini

Comments

Patrice T 3-Nov-23 23:33pm

+5

k5054 · Accepted Answer · 2023-11-03T04:33:00

Solution 1

C++

int ray[5] = { 2, 4, 6, 8, 10 };
int* p = ray;  // p points to ray[0]
*p = ray[2];   // assign the value of ray[2] (6) to what p points to (ray[0]) 
               // ray now is { 6, 4, 6, 8 10 }
               // p still points to ray[0];
std::cout << *p << *(p+1) << std::endl;  // prints 6 (ray[0], *p) and 4 (ray[1])

Posted 3-Nov-23 4:33am

k5054

Comments

CPallini 3-Nov-23 11:32am

5.