Thread 1 received signal SIGSEGV, segmentation fault

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i tried to debug my code using gdb i am getting error saying

Thread 1 received signal SIGSEGV, Segmentation fault

What I have tried:

here is my code

typedef struct list<br />
{<br />
    node *head;<br />
    node *tail;<br />
    int number_of_nodes;<br />
} List;<br />
<br />
typedef struct queue<br />
{<br />
    List *ptr_list;<br />
} Queue;<br />
<br />
void queue_initialize(Queue *queue_list)<br />
{<br />
//TODO<br />
    printf("hello inside queue_initialize\n");  <br />
    list_initialize(queue_list->ptr_list);<br />
    printf("hello after queue_initialize\n");<br />
    return;<br />
    }<br />
<br />
void list_initialize(List *ptr_list)<br />
{<br />
//TODO<br />
    printf("hello in list_initialize\n");<br />
    ptr_list->head=0;<br />
    printf("hello\n");<br />
    ptr_list->tail=0;<br />
    printf("hello\n");<br />
    ptr_list->number_of_nodes=0;<br />
    printf("hello after list_initialize\n");<br />
    <br />
}

when i call the function queue_initialize(Queue *queue_list) i get this output

hello before queue_initialize<br />
hello inside queue_initialize<br />
hello in list_initialize

but the expected output is

hello before queue_initialize<br />
hello inside queue_initialize<br />
hello in list_initialize<br />
hello <br />
hello<br />
hello after list_initialize

can anyone tell me whats wrong with this code? your effort is really appriciated please help me fast

i am pretty sure that error is here in these lines

ptr_list->head=0;<br />
ptr_list->tail=0;<br />
ptr_list->number_of_nodes=0;

Posted 30-Sep-20 19:15pm

gurukiran4u

Updated 1-Oct-20 0:18am

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KarstenK 1-Oct-20 4:04am

plz reformat the text it looks like copied from some HTML :-(

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CPallini · Answer 1 · 2020-10-01T00:18:00

You should dynamically allocate memory for your objects. Try, as starting point:

C

#include <stdio.h>
#include <stdlib.h>
// I assume your definition of node is compatible with the following:
typedef struct node
{
  int value;
  struct node * next;
} Node;

typedef struct list
{
  Node *head;
  Node *tail;
  int number_of_nodes;
} List;

typedef struct queue
{
    List *ptr_list;
} Queue;

void list_initialize(List *ptr_list)
{
  printf("hello in list_initialize\n");
  ptr_list->head=0;
  printf("hello\n");
  ptr_list->tail=0;
  printf("hello\n");
  ptr_list->number_of_nodes=0;
  printf("hello after list_initialize\n");
}
void queue_initialize(Queue *queue_list)
{
  queue_list->ptr_list = (List*) malloc(sizeof(List));
  // TODO: handle possible malloc failure
  printf("hello inside queue_initialize\n");
  list_initialize(queue_list->ptr_list);
  printf("hello after queue_initialize\n");
  return;
}


int main()
{
  Queue queue;
  queue_initialize(&queue);

  return 0;
}

Sandeep Mewara · Answer 2 · 2020-09-30T20:47:00

Quote:
A segmentation fault occurs when a program attempts to access a memory location that it is not allowed to access, or attempts to access a memory location in a way that is not allowed (for example, attempting to write to a read-only location, or to overwrite part of the operating system).

On Unix-like operating systems, a signal called SIGSEGV is sent to a process that accesses an invalid memory address.

For some details on Segmentation Fault[^].

Your case, most likely, your ptr_list does not have a valid value. Your queue setup looks incorrect and I am not sure if how is your Node defined (should be defined if you are getting some output).

In C, it is not the correct setup - you need to add struct keyword before the pointers for connecting them:

C++

struct Node { 
    int data; 
    struct Node* next; 
};

Would suggest to read and learn about linked list.
Refer:
Linked List Program in C - Tutorialspoint[^]
Linked List | Set 1 (Introduction) - GeeksforGeeks[^]

Thread 1 received signal SIGSEGV, segmentation fault

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