How to convert a DINT to 32-bit signed integer?

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Here is some background. I'm handling some special I/O device which provides counts as a 32-bit DWORD. I must convert the DWORD to double precision integer or DINT. What is the difference between a DINT and 32-bit integer that we already know? How do I use a DINT? Thanks!

Posted 22-Nov-10 8:53am

Jun Du

Updated 22-Nov-10 9:06am

v2

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Alain Rist 22-Nov-10 15:47pm

DINT is not a standard C++ type, it is probably defined somewhere you have access, otherwise you could not use it. Please provide the type definition. cheers,

4 solutions

Solution 4

I don't know how "Double Integer" got this name. After some digging, I am able to say its definition is actually identical to what we know as 32-bit integer today. The name seems to come from the legacy 16-bit world. This is an answer to my question.

Posted 28-Dec-10 12:40pm

Jun Du

Updated 28-Dec-10 12:41pm

v2

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Alain Rist 29-Dec-10 2:27am

What is the difference with the answer I gave one month ago?

Jun Du 29-Dec-10 8:12am

Actually no big difference from your post dated Nov 23 (but not Nov 22). Didn't quite follow what you suggested there.

Alain Rist 29-Dec-10 10:26am

Sorry, I didn't feel cryptic :)

Solution 2

Your question isn't quite clear because a double precision type is a floating point number. An integer is a whole number. You could also mean that you want QWORD instead od a DWORD. Meaning a 64 bit integer instead of 32 bit. The ISO C9X type for c would be long long and unsigned long long.

Whatever type you use, you should cast (or round floating points) properly.

http://www.cppreference.com/wiki/data_types[^]

http://msdn.microsoft.com/en-us/library/s3f49ktz%28VS.80%29.aspx[^]

Good luck!

Posted 22-Nov-10 9:27am

E.F. Nijboer

Solution 1

Hi !!!

Could you please provides few lines, like where you are stucked exactly?I used dint() & aint() in fortran a long back. I will be much pleased to help you?

Posted 22-Nov-10 9:24am

@Intersect☺™

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Jun Du 22-Nov-10 18:33pm

This is the feedback I got from the vender:

"Double Integer. This is usually a 32-bit integer, with the 32nd bit being the sign bit. The lower and upper limits of a DINT are -2147483648 and 2147483647."

I am still struggling at what the difference is between this DINT and the 32-bit integer we used everyday.

Jun Du 30-Nov-10 14:26pm

I don't know how "Double Integer" got this name. After some experiments, I am able to say its definition is actually identical to what we know as 32-bit integer today. Maybe the name came from the 16-bit legacy, I guess.

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Alain Rist · Accepted Answer · 2010-11-22T20:00:00

Solution 3

Hi Jun,

Your DINT type looks like an exotic name for the good old INT defined in WinNT.h (a 32 bits signed integer on Windows supported 32 and 64 bits platforms).

So

#include <WinNT.h>
typedef INT DINT;

should be enough :)
cheers,
AR

Posted 22-Nov-10 20:00pm

Alain Rist