Open a program in C# from command prompt with arguments

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I'm trying to open an exe file from C# Code. But that exe does not open directly , it open from cmd and require an argument before running. I've found many piece of codes but everyone is talking about to open CMD from C#. I'm confuse how to run a command inside CMD from C# Code , which also require and command as well?

What I have tried:

This is I've been trying yet.

C#

 ProcessStartInfo startInfo = new ProcessStartInfo();

 //startInfo.WindowStyle = ProcessWindowStyle.Hidden;

 startInfo.WorkingDirectory = "C:\\Program Files (x86)\\Maxim Integrated Products\\MPC\\MAX32550";
// In this directory there is an "abc.exe" file that I want to open and that exe cannot be start without providing an argument "abc.ini" .
 startInfo.FileName = "cmd.exe";

 MpcProc.StartInfo = startInfo;

 MpcProc.Start();

Posted 26-Mar-18 1:02am

Ammar Shaukat

Updated 26-Mar-18 1:26am

v2

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OriginalGriff · Accepted Answer · 2018-03-26T01:27:00

Solution 2

You need to set the Working directory, or it remains the same as the "Parent" process:

ProcessStartInfo psi = new ProcessStartInfo(pathToExe, arguments);
psi.WorkingDirectory = Path.GetDirectoryName(pathToExe);
Process.Start(psi);

Posted 26-Mar-18 1:27am

OriginalGriff

Comments

Ammar Shaukat 26-Mar-18 7:35am

This is working , Thanks.

OriginalGriff 26-Mar-18 7:38am

You're welcome!

F-ES Sitecore · Accepted Answer · 2018-03-26T01:06:00

Solution 1

Forget cmd, that's just a console app to let people run commands. Start the process directly and pass the required arguments to it

Process.Start Method (String, String) (System.Diagnostics)[^]

Posted 26-Mar-18 1:06am

F-ES Sitecore

Comments

Ammar Shaukat 26-Mar-18 7:15am

It worked but Still there is a configuration error. I'm not sure but there might be some problem with provided argument.

Process.Start(@"C:\Program Files (x86)\Maxim Integrated Products\MPC\MAX32550\mpc.exe", "mpc.ini");