Minute convert into Hour

Question

0.00/5 (No votes)

See more:

SQL-Server-2008R2

Dear,

I have two Column Start & End both are Datetime data type.

The Data is

Start End
12:30 15:00

The Total min is 150
i used below query

DATEDIFF(mi, dbo.Trn_Daily3.Dr_TimeStart, dbo.Trn_Daily3.Dr_TimeEnd)

Its giving correct result=150

But when i convert into hour

DATEDIFF(mi, dbo.Trn_Daily3.Dr_TimeStart, dbo.Trn_Daily3.Dr_TimeEnd)/60

then result is 2 but actual 150/60=2.5

How to do it.

Please help on this

Thanks
Basit.

Posted 19-Nov-15 0:17am

basitsar

Updated 19-Nov-15 0:20am

v2

Add a Solution

3 solutions

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

CPallini · Accepted Answer · 2015-11-19T00:25:00

Solution 3

Try

SQL

DATEDIFF(mi, dbo.Trn_Daily3.Dr_TimeStart, dbo.Trn_Daily3.Dr_TimeEnd)/60.0

See "/ (Divide) (Transact-SQL)"[^]

Posted 19-Nov-15 0:25am

CPallini

Comments

basitsar 23-Nov-15 23:53pm

Thanks A lot.

CPallini 24-Nov-15 2:32am

You are welcome.

PANKAJMAURYA · Accepted Answer · 2015-11-19T00:25:00

Solution 2

Use this code to get hour

SQL

DATEDIFF(mi, dbo.Trn_Daily3.Dr_TimeStart, dbo.Trn_Daily3.Dr_TimeEnd)/60.0

Posted 19-Nov-15 0:25am

PANKAJMAURYA

Comments

basitsar 23-Nov-15 23:53pm

Thanks A lot.

Patrice T · Accepted Answer · 2015-11-19T00:24:00

Solution 1

Did you try to divide by a non integer ?
Try to replace

SQL

DATEDIFF(mi, dbo.Trn_Daily3.Dr_TimeStart, dbo.Trn_Daily3.Dr_TimeEnd)/60

with

SQL

DATEDIFF(mi, dbo.Trn_Daily3.Dr_TimeStart, dbo.Trn_Daily3.Dr_TimeEnd)/60.0

as for many languages like C, C++, C#
a divide of integers result in an integer.

Posted 19-Nov-15 0:24am

Patrice T

Updated 19-Nov-15 0:25am

v2

Comments

basitsar 23-Nov-15 23:53pm

Thanks A lot.