The Insider News

using: yield return Enumerable.Empty<T>

would require the return type of the Function to be:

IEnumerable<IEnumerable<T>> 

and, in the context of Linq enumeration, return without yield will result in an error.

And, that would mean you could not use yield return someinstanceofT;

Richard Deeming wrote:

return from the method without issuing any yield return

BillWoodruff wrote:

the result of 'yield return null' and 'yield break' are the same

static IEnumerable<string> YieldReturnNull()
{
    yield return null;
}

static IEnumerable<string> YieldBreak()
{
    yield break;
}

static void Main()
{
    Console.WriteLine("Yield return null:");
    foreach (string item in YieldReturnNull())
    {
        Console.WriteLine("Item: {0}", item);
    }
    Console.WriteLine();
    
    Console.WriteLine("Yield break:");
    foreach (string item in YieldBreak())
    {
        Console.WriteLine("Item: {0}", item);
    }
    Console.WriteLine();
}

Yield return null:
Item: 

Yield break: