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You low on caffeine Mycroft? 
You can't cast a string to an int - the compiler won't let you... 
The only instant messaging I do involves my middle finger.
English doesn't borrow from other languages.
English follows other languages down dark alleys, knocks them over and goes through their pockets for loose grammar.
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Middle of the afternoon, hot sun, excellent bottle of white, should leave the bloody computer alone. Thank you for the redirection.
Never underestimate the power of human stupidity
RAH
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Middle of the morning, p*ssing down, pint glass of water... 
The only instant messaging I do involves my middle finger.
English doesn't borrow from other languages.
English follows other languages down dark alleys, knocks them over and goes through their pockets for loose grammar.
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Try:
int months;
if (int.TryParse(myTextBox.Text, out months))
{
myDateTimePicker.Value.AddMonths(months);
}
The only instant messaging I do involves my middle finger.
English doesn't borrow from other languages.
English follows other languages down dark alleys, knocks them over and goes through their pockets for loose grammar.
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We have a managed C# DLL registered for COM interop. This DLL can be called from either a managed or unmanaged application where the customer can control the size and position of the DLL. In our demo application, we use the following win32 API functions to call the DLL. The problem we're running against is that we're losing mouse functions on toolstrip menu items after clicking in the form, even though the hot keys will still work using the keyboard. All controls work initially until clicking on the title bar (which I omitted) or certain controls on the main form.
[DllImport("user32.dll")]
public static extern IntPtr SetParent(IntPtr hWndChild, IntPtr hWndNewParent);
[DllImport("user32.dll", SetLastError = true)]
public static extern bool MoveWindow(IntPtr hWnd, int X, int Y, int nWidth, int nHeight, bool bRepaint);
[DllImport("user32.dll", SetLastError = true)]
static extern IntPtr FindWindow(string lpClassName, string lpWindowName);
private void btnAdopt_Click(object sender, EventArgs e)
{
hWndDocked = (IntPtr)FindWindow(null, "DLL-Title";);
hWndOriginalParent = SetParent(hWndDocked, this.Handle);
MoveWindow(hWndDocked, 125, 25, iWidth, iHeight, true);
}
Some of the DLL dropdowns we can make work by changing the Parent Handle below in close event:
SetForegroundWindow(Global.ParentHandle);
Hopefully my explanation is clear, but has anyone run across this problem? Is there a better way of setting and controlling the DLL handles without losing certain mouse functionality? How can I make this work or what am I doing wrong?
Thanks in Advance,
Rick
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It's difficult to tell exactly what you are doing, but if you are changing the parent of an active window that could quite easily mean that all mouse clicks are being redirected to the wrong window.
Veni, vidi, abiit domum
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Hi Richard,
Thanks for your reply! Our self contained DLL application is called from a client's application that needs to be run within their "form/app". In my Demo, I set their app as the parent by using SetParent win32 API, but then I lose the mouse clicks on several controls. So your description in your reply appears to be accurate.
Most of our controls are now working by using the win32 API, SetForegroundWindow(ParentForm.Handle), switching the handle of our form to their app handle, in the click events of the user controls; buttons, combobox, panels, grids, etc.
I still have a problem when clicking on a disabled button/control. Actually, every mouse click needs to be trapped and handled.
How do you get the mouse click of a disabled control?
Or is there a better way of doing this?
Thanks,
Rick
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I'm not sure I understand what this is all about, there is no such thing as a self contained DLL application. A DLL is a library that provides classes and/or functions for an executable application. Also your description does not really explain what services your DLL provides to the client application, or why you are trying to switch around owners of windows.
RickiB wrote: How do you get the mouse click of a disabled control?
You don't; it is disabled in order to prevent it receiving input.
Veni, vidi, abiit domum
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Hi, I am developing an application which has a WebBrowser control.
By default WebBrowser uses Internet Explorer rendering engine.
Can we change it to Firefox or Google Chrome?
Thanks
Sai
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Thank you Rayhan. I'll look into them.
Thanks
Sai
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I'd like to add Awsomium[^] 
Bastard Programmer from Hell 
If you can't read my code, try converting it here[^]
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A postfix expression evaluator works on arithmetic statements that take this form: op1 op2 operator . . . Using two stacks, one for the operands
and one for the operators, design and implement a Calculator class that
converts infix expressions to postfix expressions and then uses the stacks
to evaluate the expressions.
This is homework. But I completely could not understand what to do.
Please tell me what to do.
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This is an exciting opportunity for you to really increase your programming skills and mastery !
I really can't tell you "what to do" since that would defeat the whole purpose of your education, but I can provide some "clues" that may be useful:
0. know that CodeProject is your friend [^].
1. talk to your teacher, and fellow students: if all the other people in the class are at the same level you are, then probably the others are also finding the problem difficult: ask their advice. if most other people in the class are very advanced compared to you, and the teacher, and your fellow students, are not willing to guide you, reconsider whether you are ready for this course at this time.
2. but, before you talk to your teacher, do the study required to make sure you have a sound knowledge of what infix and postfix notation is, what a stack is.
3. be aware that parsing (interpreting) infix notation of the standard form involves recursion. you have both the native operator precedence rules ... like "multiply before add" ... and the fact that the use of parentheses can change the order in which operators are evaluated.
Study hard, work hard, learn from your mistakes; accept that making mistakes is inevitable, and that acquisition of deep understanding and skill often involve the simultaneous development of both.
bill
Google CEO, Erich Schmidt: "I keep asking for a product called Serendipity. This product would have access to everything ever written or recorded, know everything the user ever worked on and saved to his or her personal hard drive, and know a whole lot about the user's tastes, friends and predilections." 2004, USA Today interview
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Here are some tips I hope are useful to you.
1. One problem at the time. Read your assignment and write down what smaller problems you encounter. Then solve each problem at the time. eg. One problem could be that you need to go from input to calculating output. Divide that and you come to sub-problems: getting the input. Split the input. Do base calculations (+,-,/,*, ...). provide output. Here you can devise another issue. What to do with errors and exceptions, etc... The smallest problems "should" be solvable (and preferably reusable  ).
This is an art were many, many, many developers fail ending with programs way too complex...
2.Find sample applications of other calculator applicatons, chances are, someone did something you can re-use.
3. Prototype
If you're not sure about something you want to implement.
hope this helps.
modified 27-Oct-13 15:46pm.
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I am trying to make a serial port terminal and i have succesfully made it except for some problems that i am facing.
i have a button pressing which the terminal starts and the data from the serial port start to get displayed on the textbox.
when i press the button again the serial port closes.
Also i have put the code to read from the serial port in a timer with a time of 1 millisecond. So it automatically works like a loop and the data can be displayed continuously.
Case 1. when i try reading from the serial port using
_SerialPort.ReadLine ()
what happens is that the data is getting displayed perfectly, but i am not able to press the button again to close the serial port, also i cant even close the application. I would have to use the task manager to kill the process.
Case 2. when i try reading from the serial port using
_SerialPort.ReadExisting ()
what happens is that the earlier issue is resolved, but the data that is received is not continuous, that is some values are not recieved.
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ReadLine() blocks until a new line character occurs so you can't expect it to do anything immediately based on a key press unless the key causes a end of line.
If your source for the characters are human input is human than it seems unlikely that ReadExisting() would lose anything. What would be more likely in that case is that your output code is not correctly handling what ReadExisting is returning.
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jschell wrote: If your source for the characters are human input is human than it seems unlikely that ReadExisting() would lose anything.
the characters are not human input. its source is a micro controller ADC output. So it continuously sends data to the serial port.
Parity - Even
Databits - 8
Stopbits - 2
Baudrate - 4800
jschell wrote: ReadLine() blocks until a new line character occurs so you can't expect it to do anything immediately based on a key press unless the key causes a end of line.
The button press calls the
serialport.Close();
so then it shouldn't matter what the
ReadLine() function gets.
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Don't use either of them like that.
Instead, handle the SerialPort.DataReceived[^] event, and get the data in that using ReadExisting - you can then add the data to the textbox in the event handler and you should never lose any data, nor should your UI freeze up.
Remember, Serial ports are very slow devices - data transfer is not instantaneous, nor is it packet based. if you are running your serial port as 9600 baud for example, it will receive one character about every millisecond (7 data bits, 1 parity, 1 start and one stop bit == 10 bits, 9600/10 = 960 characters per second.)
So if you just read once, you will get whatever characters are in teh buffer at that moment, and nevr get any more.
The only instant messaging I do involves my middle finger.
English doesn't borrow from other languages.
English follows other languages down dark alleys, knocks them over and goes through their pockets for loose grammar.
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OriginalGriff wrote: Instead, handle the SerialPort.DataReceived[^] event, and get the data in that using ReadExisting - you can then add the data to the textbox in the event handler
Sorry forgot to mention, i had tried that too...
Same problem. losing data....
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How did you use it? Do you still have the code?
The only instant messaging I do involves my middle finger.
English doesn't borrow from other languages.
English follows other languages down dark alleys, knocks them over and goes through their pockets for loose grammar.
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private void Start_Click (object sender, EventArgs e)
{
if(Start.Text == "Start")
{
Start.Text = "Stop";
_SerialPort.DataReceived += new SerialDataReceivedEventHandler (Port_DataReceived);
}
else
{
Start.Text = "Start";
}
}
private void Port_DataReceived (object sender, SerialDataReceivedEventArgs e)
{
string data = _SerialPort.ReadExisting ();
rtbTerminal.AppendText (data);
rtbTerminal.ScrollToCaret ();
}
private void Start_Click (object sender, EventArgs e)
{
if(Start.Text == "Start")
{
Start.Text = "Stop";
_SerialPort.DataReceived += new SerialDataReceivedEventHandler (Port_DataReceived);
}
else
{
Start.Text = "Start";
}
}
private void Port_DataReceived (object sender, SerialDataReceivedEventArgs e)
{
string data = _SerialPort.ReadExisting ();
rtbTerminal.Invoke (new EventHandler (delegate
{
rtbTerminal.SelectedText = string.Empty;
rtbTerminal.AppendText (data);
rtbTerminal.ScrollToCaret ();
}));
}
I have tried both ways above.
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Um.
You do realize that each time you click the "Start" button, you add another handler to the existing list? So when a character arrives, the same handler method will be called twice, then three times, then four, etc...
And that DataReceived is likely to be called each time a character arrives, since your PC runs rather faster than the serial port does, most of the time?
How I would start:
Add the handler once, when you first construct the SerialPort instance.
Add a bool to enable / disable receive.
When you press the Start button, clear the text from the RTB, then set the bool to enabled.
When you press the Stop button, set the bool to disabled.
In the DataReceived Handler, read the data available. Then, check the bool. If it is enabled, Append the data to the RTB and scroll to the caret. (You shouldn't need an invoke, I don't think). Do not clear the RTB.
If it is disabled, throw the data away!
Try that...
The only instant messaging I do involves my middle finger.
English doesn't borrow from other languages.
English follows other languages down dark alleys, knocks them over and goes through their pockets for loose grammar.
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I have two forms, the first one is the main form and creates the serial port instance and then i pass the serial port object into the second form which is the terminal form.
The following code is the contents of the namespace of the second form
bool Receive_Enable = false;
public Terminal (SerialPort Serial_Port)
{
InitializeComponent ();
_SerialPort = Serial_Port;
_SerialPort.Close ();
_SerialPort.DataReceived += new SerialDataReceivedEventHandler (Port_DataReceived);
}
private void Start_Click (object sender, EventArgs e)
{
if(Start.Text == "Start")
{
Start.Text = "Stop";
_SerialPort.Open ();
Receive_Enable = true;
}
else
{
Receive_Enable = false;
_SerialPort.Close ();
Start.Text = "Start";
}
}
private void Port_DataReceived (object sender, SerialDataReceivedEventArgs e)
{
if(Receive_Enable)
{
rtbTerminal.AppendText (Convert.ToString (_SerialPort.ReadLine ()));
rtbTerminal.ScrollToCaret ();
}
}
Tried this....
Also tried with
_SerialPort.ReadExisting ()
The application freezes after few seconds.... 
What to do???? 
Am i doing this right???
modified 25-Oct-13 1:26am.
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