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How about this:
<br />
<br />
foreach (var tb in new TextBox[] { txt1, txt2, txt3, txt4, txt5, txt6, txt7 }) {<br />
if (tb.Text == "") {<br />
ErrorLabel.text = string.format("Enter something in {0}", tb.Name);<br />
tb.Focus();<br />
break;<br />
}<br />
}<br />
<br />
It aint pretty, and I'd prefer data binding, but it'd work?
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If you set required field validators when tabbing to each textbox it instantly does validation i dont see the issue perhaps ive misinterperted your query
A pessimist sees the difficulty in every opportunity; an optimist sees the opportunity in every difficulty I am a Optimist
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That's what I would do too... so it must be wrong somehow. 
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I'll give this a shot .. looks interesting
I'd do databinding, but not sure how. I'm still new at this. If I created the DB within Visual Studio I'd be able to do it, but it's created at runtime (SQL CE)
EDIT: I just tried it, and it worked great. Thanks!!!
modified on Friday, April 4, 2008 1:36 PM
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Or set the Button's Enabled property
btn.Enabled = ( txt1.Text.Length > 0 ) && ... ;
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i know this is quite the inapropriate place to ask but i am not getting any answers from the truevision site concerning the 6.5 and it's mousepick train of code. i tried it but the mouse keeps on picking the wall behind the meshes i had set to rotate.
what i am trying to say is i set a wall and three meshes before it to rotate that way if you click on one of the meshes an event will occur but the event keeps on happening to the wall instead. what should i do?
help please
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anarchi23 wrote: what should i do?
sounds like A) you have not bitmasked your picking objects B) you have not cleared your events so they stay on the event stack C) you are unfamiliar with the environment and the confusion runs deeper D) you are unfamiliar with the language and the confusion runs even deeper still.
If you are not getting answers at the truevision forums, the answer may be at the core language, C#. Since I see you recently joined only to cross post, you aren't likely to get many answers, but you might if you phrased it better.
The process you are describing is a 3D problem, but the code that it is uses is obvious a language issue. Not understanding either means you aren't likely to even know which problem is which or where it should be. That is bad news. Brush up on your C# related to the activities being used to narrow this down to a 3D issue not a language use issue. Once you have that down, someone, though there are few of us here, may be able to help. There are very few 3D graphics programmers here and fewer still in C#.
_________________________
Asu no koto o ieba, tenjo de nezumi ga warau.
Talk about things of tomorrow and the mice in the ceiling laugh. (Japanese Proverb)
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Hello everybody
I have created a table in a data base and I want to use a DataSet to insert in this table while using the TableAdapter.
Normally that this fact grace has the method Insert but that doesn't work. The primary key of the table increments itself automatically.
And when I execute the request to the level of the DataSet that walks very well. You have some ideas.
Thank you for advance
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hi
i have asked this question before as i dint got any answer i am repostingwu it with a clear format
i have a tree view in my form
i want to get the key value of the node
e.node.name returns the key value but it appears under few events
i want to get the key value any where in the form where i need it
please please do reply
Dont Get Paid for the Hours you worked, Get Paid for the Work You Have Done in an Hour.
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simple...
TV.Nodes[XX].Name
XX is index
TVMU^P[[IGIOQHG^JSH`A#@`RFJ\c^JPL>;"[,*/|+&WLEZGc`AFXc!L
%^]*IRXD#@GKCQ`R\^SF_WcHbORY87??6?N8?BcRAV\Z^&SU~%CSWQ@#2
W_AD`EPABIKRDFVS)EVLQK)JKSQXUFYK[M`UKs*$GwU#(QDXBER@CBN%
Rs0~53%eYrd8mt^7Z6]iTF+(EWfJ9zaK-i?TV.C\y<p?jxsg-b$f4ia>
--------------------------------------------------------
128 bit encrypted signature, crack if you can
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it will return the name not the key value or key string
Dont Get Paid for the Hours you worked, Get Paid for the Work You Have Done in an Hour.
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key??? what do you mean by key
you can use Text property for value...
TVMU^P[[IGIOQHG^JSH`A#@`RFJ\c^JPL>;"[,*/|+&WLEZGc`AFXc!L
%^]*IRXD#@GKCQ`R\^SF_WcHbORY87??6?N8?BcRAV\Z^&SU~%CSWQ@#2
W_AD`EPABIKRDFVS)EVLQK)JKSQXUFYK[M`UKs*$GwU#(QDXBER@CBN%
Rs0~53%eYrd8mt^7Z6]iTF+(EWfJ9zaK-i?TV.C\y<p?jxsg-b$f4ia>
--------------------------------------------------------
128 bit encrypted signature, crack if you can
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ALT + F4 wrote: hi
i have asked this question before as i dint got any answer i am repostingwu it with a clear format
Well. Aren't you the little liar? You posted this a few posts below and you did get an answer - just because it wasn't exactly right, you shouldn't post porkies here - you will be found out. It's polite to continue on the original thread, and not to cross or multiple post.
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dude i have confessed that i have started a new thread .. in my post...
I wonder most of the mvp's are much bothered about the cross posts and most of them have a single answer for all the questions " What is Google "
SO please do not give unexpected reply's as We all expect answers from U all..
I hope u got it if not leave it ...
Still how to get the key value ?
I have tried in many ways using key value we can get the name
i want to use name and get the key ..
Dont Get Paid for the Hours you worked, Get Paid for the Work You Have Done in an Hour.
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ALT + F4 wrote: dude i have confessed that i have started a new thread .. in my post...
Yes - and you said you had no answers which was a blatant untruth.
ALT + F4 wrote: wonder most of the mvp's are much bothered about the cross posts and most of them have a single answer for all the questions " What is Google "
We are bothered by the multi and cross posts because they make it almost impossible for others to find answers to problems because answers end up spanning multiple threads. This isn't a private email conversation, it's a thread that others may follow to answer issues they have.
The reason we tell people about Google is that it is very obvious that people post questions without doing ANY research for themselves, and that's just lazy.
I reckon that about 90% of the questions asked in these forums could be answered in a couple of minutes by the poster actually getting off their a*se and looking at google for a couple of minutes. It's not hard. It's not rocket science. It's just the type of thing that I do myself before I ask a question.
Do you see me or the other MVPs asking lots of questions on the forums? No? That's because we've mastered the basic technique of looking for information for ourselves; it's not because we know every class in the .NET framework inside out.
ALT + F4 wrote: Still how to get the key value ?
You still haven't explained what your problem actually is. You've thrown a disjointed and rambling thread together that doesn't tell us anything. What key? What name? Do you mean from a dictionary class? If so, take a look at this sample:
public string FindByName<T>(T dictionary, string name)
{
return dictionary[name];
}
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As far as I can tell, a System.Windows.Forms.TreeNode doesn't have a key property.
MSDN[^] for a full listing of Methods and Properties.
Maybe use a dictionary Dictionary<int, TreeNode> TreeNodeDictionary and populate your treeview from this?
Dave
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I know I have written the code on drag & drop feature for file interpretation in the past but can't seem to find the code. So I'm googling this online and hopefully you could give me some help with this.
This is what I wanted: I would drag & drop the multiple text files into the target application (without opening the application itself), I would show the file names that I have drag & dropped into the app.
that's all I need to do. I can do the rest of the coding.
I know I have placed the code in Main() in visual studio 2003 but where is that in visual studio 2005?!?!?
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Blubbo wrote: I know I have placed the code in Main() in visual studio 2003 but where is that in visual studio 2005?!?!?
you have a program.cs file, it's in there.
led mike
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right... I just found it just before you repled.
This is what I wrote... I may be wrong... pls correct me...
code shown below:
using System;
using System.Collections.Generic;
using System.Windows.Forms;
namespace UManager_Interpeter
{
static class Program
{
// <summary>
// The main entry point for the application.
// </summary>
[STAThread]
static void Main(string[] fileList)
{
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
Application.Run();
foreach (string file in fileList)
{
MessageBox.Show(file + " was dropped into app!");
}
}
}
}
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P.S. How do I get the Main() pickup the name of files that I drag & dropped into app?
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Blubbo wrote: P.S. How do I get the Main() pickup the name of files that I drag & dropped into app?
I don't understand "pickup the name of files". They are in the args array if the user dropped them on the Applications Icon in Windows Explorer.
class Program
{
static int Main(string[] args)
{
led mike
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AAAAHH!!! Solved!!!!
Thanks a heap! You have answered my question... I knew I had to put strings[] in Main() but didn't come out right.
That was until I noticed... "static class Program"
I HAD to remove "static" to get it to work.
I had like that when I wrote it before.
Again thanks a heap!
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I'm using MS WinForms ReportViewer control in local mode.
My application creates in-memory assembly EntityExtension dynamically.
Report definition refers codemodule Business which references to this assembly:
<CodeModule>EntityExtension</CodeModule>
<CodeModule>Business</CodeModule>
For running ReportViewer I use:
reportViewer1.LocalReport.ExecuteReportInCurrentAppDomain(<br />
System.Reflection.Assembly.GetExecutingAssembly().Evidence);<br />
<br />
reportViewer1.LocalReport.AddTrustedCodeModuleInCurrentAppDomain("EntityExtension");<br />
reportViewer1.LocalReport.AddTrustedCodeModuleInCurrentAppDomain("Business");
Trying to preview report causes error
An error occured during local report processing
[BC30007] Reference required to assembly EntityExtension
How to fix ?
How to force ReportViewer to find EntityExtension assemnly ?
Andrus
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I have a picturebox which was created programatically and its location should be determined when the form loads.
I set the location property to a point but no matter what point is set, the picturebox appears on a fixed location when the form loads.
Below is the code:
<br />
In the picture class:<br />
<br />
public PictureBox PlaceFlower()<br />
{<br />
PictureBox flower = new PictureBox();<br />
flower.Height = 80;<br />
flower.Width = 80;<br />
flower.Image = Image.FromFile("C:\\grass.bmp");<br />
<br />
return flower;<br />
}<br />
<br />
public Point SetCoordinates()<br />
{<br />
int x = randomClass.Next(10,50);<br />
int y = randomClass.Netxt(10,50);<br />
Point p = new Point(x, y);<br />
<br />
return p;<br />
}<br />
<br />
<br />
In the form class:<br />
<br />
private PictureBox flowerPicture;<br />
<br />
private void Form1_Load(object sender, EventArgs e)<br />
{<br />
flowerPicture = picture.PlaceFlower();<br />
flowerPicture.Location = picture.SetCoordinates();<br />
}<br />
<br />
I've checked the values of the point coordinates and they vary each time the form loads but somehow the picturebox always remain fixed at the same point on the form. I have made sure that the locked property of the control is set to false.
What is the problem with the picturebox location? 
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Hi,
some comments:
1.
your names are quite confusing, you should change them:
PlaceFlower() does not place a flower, it creates a PictureBox that holds a flower,
but it does not make it visible and does not set its location; GetFlowerBox() is a better name.
SetCoordinates() does not set coordinates, it creates and returns a Point, but does
not do anything with the Point. GetRandomPoint() would be a more appropriate name.
Choosing proper names will help you in understanding your own code, today and in future.
2.
your code is not complete, and the problem is likely to reside it what is not shown.
My best guess is you have two PictureBoxes:
- if you already see a flower, it is not the one from flowerPicture; I suspect you
have some other PictureBox that shows the flower you see, and is not affected by
your attempts to move it;
- the flowerPicture PictureBox, as far as the code shows, never becomes visible, since
it is not added to the Controls property of any Container or Form.
Luc Pattyn [Forum Guidelines] [My Articles]
This month's tips:
- before you ask a question here, search CodeProject, then Google;
- the quality and detail of your question reflects on the effectiveness of the help you are likely to get;
- use PRE tags to preserve formatting when showing multi-line code snippets.
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