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I have created some module in C#.net Visual studio 2005. Now I want to incorporate them under a single project.I need to assign the permission of each module's Controlls based on User previllage. So to assign the permission I think, I need to know all modul's forms and control. It may get from each modul's design.cs file easily. but I want to access them from a MDI form where all module are chiled of that MDI and want to assign permission based on user previllage.Now question is that how can get the all modul's forms and control's properties from that MDI form.

Dear SayemAhmed!
It is not possible to get all the properties name except from the .cs file.
Thanx.
NNur

Reposting the same question won't change the answer. What you want to do is not practical and a nightmare to support. Each module/form/whatever in your app should be checking the user object you have and responding accpordingly itself. Try to go through the entire project and "set this, setup that, change this" is extrodinarily inefficient and the code must be updated coninuously as the application changes.

A guide to posting questions on CodeProject[^]

Dave Kreskowiak
Microsoft MVP
Visual Developer - Visual Basic
2006, 2007, 2008

Hi,

which are the best pratices of using xml as database? can i query it like in sql server? wher linq fits here?

links appreciated thanks Big Grin | :-D

nelsonpaixao@yahoo.com.br

trying to help & get help

Using XML as a database is generally a bad idea because it's a lot slower than using an actual database. LINQ helps a little, but I certainly wouldn't want to write a crapload of code to do it. Not only do you have to load/save the data continuously, you have to worry about rolling back transactions, and other stuff that the database server usually takes care of.

Generally, if the data in your XML file exceeds 1mb, and has more than just a few "tables", it's a better idea to use a real database.

"Why don't you tie a kerosene-soaked rag around your ankles so the ants won't climb up and eat your candy ass..." - Dale Earnhardt, 1997
-----
"...the staggering layers of obscenity in your statement make it a work of art on so many levels." - Jason Jystad, 10/26/2001

Hi,

how can i save the contents of a dgv to a xml file?
i know how to read from xml to dgv. because the dataset has more that one table and the datagrid only display one table, im affraid o mess it when saving.
I Checking it know, but if anyone can direct me to some link or code would be helpfull Big Grin | :-D

nelsonpaixao@yahoo.com.br

trying to help & get help

Move your data to a DataSet/DataTable object(s) and the rest is easy. It's save to an XML file in one statement.

A guide to posting questions on CodeProject[^]

Dave Kreskowiak
Microsoft MVP
Visual Developer - Visual Basic
2006, 2007, 2008

cast your datagridview.DataSource to DataTable then save its contents to XML file

DataTable myDataTable =(Datatable)dgv.DataSource;
myDataTable.WriteXml(filename);

hope it helps

dhaim
ing ngarso sung tulodho, ing madyo mangun karso, tut wuri handayani. "Ki Hajar Dewantoro"
in the front line gave a lead, in the middle line build goodwill, in the behind give power support

I have given a task to do a rough design document on instrumentation (tracing) plan in our application. Can anybody please give me link to good article or share their ideas? (I searched , still searching for good article.)

Thanks.

Hi,

I have png and xml files embedded in a project. I can access them with the code bellow.

DataSet MyDataSet = new DataSet();
Assembly ThisAssembly = Assembly.GetExecutingAssembly();
// assign a image png to button 
Stream Stream_Image = ThisAssembly.GetManifestResourceStream("MyProject.Resources.info.png");
Button_Info.Image = Image.FromStream(Stream_Image);

// assign table to DataGridView
Stream Stream_Xml = ThisAssembly.GetManifestResourceStream("MyProject.Resources.users.xml");
MyDataSet.ReadXml(Stream_Xml); // why does this work???
DataGridView_Report.DataSource = MyDataSet.Tables[0];

OK.
For the png i got it, but ... for the xml why does it work? D'Oh! | :doh:

MyDataSet.ReadXml(Application.StartupPath + "\\...\\users.xml", XmlReadMode.ReadSchema));

This i understand, (not embedded although) the path way, here i really reading a xml not a stream.

nelsonpaixao@yahoo.com.br

trying to help & get help

There isn't really any difference between PNG data and XML data, it's only a bunch of bytes. Reading a stream of bytes as a PNG image or reading a stream of bytes as an XML document makes no difference for the stream that you are reading from.

Despite everything, the person most likely to be fooling you next is yourself.

There is no difference at all. When you pass a path it goes and opens the file (which ends up as a stream), and when you pass it a stream - well, its already a stream.

A stream is just a pile of data, in memory, on your hard disk, coming over a network; it's all quite similar.

My current favourite word is: Nipple!

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Game Programming articles start -here[^]-

Ok then i got it.
The more i know the more i realize i dont know Laugh | :laugh:

thanks

nelsonpaixao@yahoo.com.br

trying to help & get help

Hey, i have this form that makes a grid of buttons, and when you click on the button it changes color.

The point of this is so i can do a check later and if the button is green i will turn on something.

Problem is it doesn't seem to save my settings, infact it doesn't seem to read the settings.default values after drawing

The settings look like:
Name | Type | Scope | Value
Mon0 Bool User True
Mon1 Bool User True
Mon2 Bool User False //and so forth for the next 165 options

        void CreateButton() 
	{ 
	 
	    List<list><button>> btns=new List<list><button>>(); 
	 
	        string[] day = new string[] { "Mon", "Tue", "Wed", "Thu", "Fri", "Sat", "Sun" }; 
	        int hour = 24;
                string name;
	 
	        for (int i = 0; i < day.Length; i++) 
	        { 
	            List<button> buttons = new List<button>(); 
	            for (int j = 0; j < hour; j++) 
	            { 	                
	                Button btn = new Button(); 
	                btn.Name = GenerateButtonName(day[i],j);
                    name = btn.Name.Substring(3);              
                foreach (SettingsProperty currentProperty in Properties.Settings.Default.Properties)
                    {
                        if (currentProperty.Name == name)
                        {
                            if (currentProperty.DefaultValue.Equals("True"))
                            {
                                btn.BackColor = System.Drawing.Color.Green;
                            }
                            else
                            { 
                                btn.BackColor = System.Drawing.Color.LightGray;
                            }
                        }
                    }                                               
                    btn.Location = new System.Drawing.Point(445, 130);
                    btn.Size = new System.Drawing.Size(14, 14);
                    btn.Click += new System.EventHandler(btn_Click);
	            buttons.Add(btn);
                    tableLayoutPanel1.Controls.Add(btn, j, i); 
	            } 
	            btns.Add(buttons);    
	        }  
	} 


        private void btn_Click(object sender, EventArgs e)
        {
            string senderName;
            senderName = ((System.Windows.Forms.Button)sender).Name.Substring(3); 
   
            if (((System.Windows.Forms.Button)sender).BackColor == System.Drawing.Color.Green)
            {
                ((System.Windows.Forms.Button)sender).BackColor = System.Drawing.Color.LightGray;    
                foreach (SettingsProperty currentProperty in Properties.Settings.Default.Properties)
                {
                    if (currentProperty.Name == senderName)
                    {                              
                            currentProperty.DefaultValue = "False";
                        //TODO: Add a exit call
                    }
                }        
            }
            else
            {
                ((System.Windows.Forms.Button)sender).BackColor = System.Drawing.Color.Green;
                foreach (SettingsProperty currentProperty in Properties.Settings.Default.Properties)
                {
                    if (currentProperty.Name == senderName)
                    {
                        currentProperty.DefaultValue = "True";                        
                    }
                } 
            }          
        }
</button></button></button></list></button></list>

I have a button on the form that calls the Properties.Settings.Default.Save().
It does draw the buttons, according to the settings, the first 3 are green, the rest are grey, but when i put in a statement that made a label equal the value of Mon0, even though the values are drawing as True and the tabel in the settings says true, its returning the value False.

Can anyone help! I'v been ripping my hair out over this for days! Let me know if you need more info or want a copy of the project.

The RichTextBox control's Text property displays a dropdrown option so you can enter multiple lines of entry.

I was wondering if there was a way to do this with a custom Text property. I understand it'd probably have to do with the Designer() ComponentModel option, but I don't know how to handle it.

Thanks

One of my articles might be able to help you: Targeting Design-Time Events of UserControls[^]

Regards,
Thomas Stockwell

Programming today is a race between software engineers striving to build bigger and better idiot-proof programs, and the Universe trying to produce bigger and better idiots. So far, the Universe is winning.

Visit my Blog

Almost

turns out it requires the import of a hidden Forms.Design form:

[Editor(@"System.Windows.Forms.Design.StringCollectionEditor, System.Design,
 Version=2.0.0.0, Culture=neutral, PublicKeyToken=b03f5f7f11d50a3a",
typeof(System.Drawing.Design.UITypeEditor))]

But thanks anyway!

Hi all ,
i tried to add space to my richtextbox when i click button by this way

richtextbox1.text[position]= ' '

but it didn't work because the properity is read only
i need another way to do that
thx

You can use Text and Rtf properties of richtextbox class

Giorgi Dalakishvili

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thx for ur reply but i want an example plz

How about a lil reading before asking ...

did you ever check richTextBox.Rtf.Insert(int position, string somechar) or richTextBox.Text.Insert(int position, string somechar) ? Hmmm | :|

I have a C# program that needs to access a webpage, and then send data back to the same webpage, either by POST or GET (both work in firefox), except both POST and GET methods give me the same problem in C#.

I load the page successfully, without issues, using a WebRequest, I obtain the embedded resources correctly, I even generate the response URL / POSTDATA I require correctly, except when it comes to using this URL / POSTDATA it returns a failure page as opposed to the success page I expect.

Copying and pasting the generated GET URL into firefox gives me the success page, as does using the page normally with POST, but creating a new WebRequest with that exact same URL or POSTDATA... fails every time.

Is there any particular reason this is occuring? I have all the correct headers, cookies, etc.

how does calling a webpage differ from FireFox to C#?

Any help would be apreciated.

There is no difference. Firefox just makes a request, just like your program. There has to be something that you are doing differently in you request.

Despite everything, the person most likely to be fooling you next is yourself.

1)

WebRequest wrq1 = WebRequest.Create("http://a.b.com/site.php?uid=*********");
        WebResponse wrs1 = wrq1.GetResponse();
        StreamReader sin = new StreamReader(wrs1.GetResponseStream());
        .
        .
        .
        wrs1.Close();

2)

WebRequest wrq2 = WebRequest.Create("http://a.b.com/rsrc.php?#Referer=http://a.b.com/site.php?uid=********");
        wrq2.Headers.Add(HttpRequestHeader.AcceptLanguage, "en-gb,en;q=0.5");
        wrq2.Headers.Add(HttpRequestHeader.AcceptEncoding, "gzip,deflate");
        wrq2.Headers.Add(HttpRequestHeader.AcceptCharset, "ISO-8859-1,utf-8;q=0.7,*;q=0.7");
        wrq2.Headers.Add(HttpRequestHeader.KeepAlive, "300");
        wrq2.Headers.Add(HttpRequestHeader.Cookie, "...");
        WebResponse wrs2 = wrq2.GetResponse();
        .
        .
        .
        wrs2.Close();

3)

WebRequest wrq3 = WebRequest.Create("http://a.b.com/site.php?uid=&value=..&uniqid=************");
        //            wrq3.Headers.Add(HttpRequestHeader.AcceptLanguage, "en-gb,en;q=0.5");
        //            wrq3.Headers.Add(HttpRequestHeader.AcceptEncoding, "gzip,deflate");
        //            wrq3.Headers.Add(HttpRequestHeader.AcceptCharset, "ISO-8859-1,utf-8;q=0.7,*;q=0.7");
        //            wrq3.Headers.Add(HttpRequestHeader.KeepAlive, "300");
        //            wrq3.Headers.Add(HttpRequestHeader.Cookie, "...");
        wrq3.Method = "GET";
        WebResponse wrs3 = wrq3.GetResponse();
        .
        .
        .
        wrs3.Close();

1 and 2 work fine, and all is successful until I hit 3. Like I said, doesnt matter whether its GET or POST, Ive tried both, tried with and without headers which have seemingly no effect at all on this one. With the GET method as above, after it had failed, i copied and pasted the generated url (ive put its general form there not its actual form) into firefox and had success so I know that Im creating the URL correctly, Ive just got no idea what else is wrong. I cant think of anything.

Maybe you`re missing some javascript code that sets some cookie var somewhere locally ... also you should set the Refferer value as some sites use it. Get Live HTTP Headers for firefox and check if there isn`t any redirection or some background stuff you`re not aware of.