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Dave Kreskowiak
Microsoft MVP
Visual Developer - Visual Basic
2006, 2007, 2008

Hello,
I want to capture the pc desktop screen when any event is fired like start menu is clicked or "my documets" is opened. So for that any listener is needed to listen continuous system events?
And how i recognize when any event is fired?
Help me if anyone knows.

Why have you asked the same thing three times ?

Christian Graus

Driven to the arms of OSX by Vista.

Hello,
I have made different queries, 1. how can i open start command using mouse coordinates, 2. is there any listener is needed to listen continuously and perform task when any event is fired like open c:drive.
So please help me out for that. It will be great for me.

Hello,
I had capture the windows screen of my pc, if i click on "start", the start ,menu should be opened.
Will you please help me for doing this?

Hello,
I have developed the basic screen capturing of the remote pc to my pc, now when i click on start menu from my pc i need to open start menu on that remote pc n my pc also. So i have the coordinate of start menu but for remote pc how can i use that coordinte?
Please help me out if anyone knows .
Thank you.

I want to research broadcast, how can I get the VNC open source?

Try Google.
D'Oh! | :doh:

www.thomas-weller.de

Programming today is a race between software engineers striving to build bigger and better idiot-proof programs, and the Universe trying to produce bigger and better idiots. So far, the Universe is winning.
Programmer - an organism that turns coffee into software.

learn how to use google ...

c++ (tightvnc) http://www.tightvnc.com/download.html[^]

c# - I beleive there's a c# client here http://dotnetvnc.sourceforge.net/[^] - dont know if there's a c# vnc server

'g'

Hello everyone,

I want to generate an XML file like below. My confusion is what technologies could I use to concatenate all information into a single XML document.

The root confusion is, I have a class called teacher which matches the teacher sub-section (ID, name and major) -- which I could use serialization technologies to generate teacher part XML information.

For other parts, like department, I also have a class to represent the information -- I could also use serialization technologies to serialize the information to XML -- but it has no relationship between teachers. So, my confusion is, how to concatenate different parts altogether, like department, club and teachers, and also make the whole XML document looks like below to reflect the relationships and hierarchies between them?

<?xml version="1.0" encoding="utf-8"?>
<Department>
  <DepartmentInfo ID ="100">
    <Location> San Jose </Location>
    <Type> Computer Science</Type>
  </DepartmentInfo>
    <Clubs>
      <Club ID="200">
        <Name>Football</Name>
      </Club>
      <Club ID="201">
        <Name>Basketball</Name>
      </Club>
    </Clubs>
    <Teachers>
      <Teacher ID="300">
        <Name>Thomas</Name>
        <Major>Algorithm</Major>
      </Teacher>
      <Teacher ID="301">
        <Name>Zhou</Name>
        <Major>Linear Programming</Major>
      </Teacher>
    </Teachers>
</Department>

thanks in advance,
George

Can yo simply use XmlDocument class[^].

The need to optimize rises from a bad design.

My articles[^]

Thanks Mika,

Do you have any samples or tutorials to recommend? Smile | :)

regards,
George

No problem.

Quickly searching this site, I found several articles on XmlDocument. Have a look at them, I think you'll find several good ones: http://www.codeproject.com/info/search.aspx?artkw=xmldocument&sbo=kw[^]

The need to optimize rises from a bad design.

My articles[^]

Thanks Mika!

I like them! Smile | :)

One more question, you option to my problem solution is to generate the XML document manually, not creating a class which contains all information and serialize the class?

regards,
George

If you only have to deal with XML files created by your application (no external ones), then I'd use XML serialization, it's just so comfortable to use Smile | :)

regards

modified 12-Sep-18 21:01pm.

Thanks Greeeg,

I would also like to use serialization if I could. As I mentioned in the below URL, the issue which blocks me from using serialization is, the information are stored in different objects/classes, I do not know how to aggregate them altogether. Any ideas?

http://www.codeproject.com/script/Forums/View.aspx?fid=1649&msg=2824797[^]

regards,
George

I think you have at least three options:
1. Create the document fully manually by looping the objects you want and add the information to the document you need
2. First serialize the objects, then loop through the xml documents created by serialization, read them and copy the relevant nodes to a single document
3. Create a generic collection (or nested collections if you need) and add your objects into that collection. After that, serialize it

I guess that if you have strict requirements for the xml 'format', serialization may not produce automatically the format you need. Also you can implement ISerializable on your objects, but that may be a longer way.

The need to optimize rises from a bad design.

My articles[^]

Thanks Mika,

1.

So, in my situation, you think generate the XML document manually is the best way? Smile | :)

2.

One more question about performance, I heard serialization is always faster than writing XML document manually, is that true?

regards,
George

1. I can't say it's the best option of those I listed, it depends on (all of) your requirements.
2. This should be true since serialization is normally a process done by framework and it's optimized. When writing your own document, you have your own custom MSIL code that is executed and it can hardly compete when it comes to speed.

The need to optimize rises from a bad design.

My articles[^]

Thanks Mika,

1.

My current confusion is the information which is needed to generate the XML file are from different Types. And I do not have a single type which aggregates all of the types. So, in my situation, the best option is to generate the XML manually?

2.

Mika Wendelius wrote:
it depends on (all of) your requirements.

What other requirements are needed? For example?

regards,
George

So do you mean that in the example Navaneeth wrote, you don't have Department class that contains all the other classes?

Your XML example in the original question had Deparment as a root element which held all the other elements.

The need to optimize rises from a bad design.My articles[^]

Thanks Mika,

I decide to use similar way which Navaneeth wrote, I could wrote a upper level class to wrap all of the components, like department, teacher, clubs, etc. Smile | :)

How do you think of this solution?

regards,
George

I think it's a good one.

The need to optimize rises from a bad design.My articles[^]

You have two choice:
1. Create a function that will generate a string that will contain the xml. This method is the fastest and the most simple way to do it:

public class CClub
{
    int m_id;
    string m_name;

    public string GenerateXml()
    {
        return 
            "<Club ID=\"" + m_id.ToString() + "\">\n" +
                "<Name>" + m_name + "</Name>\n" +
            "</Club>\n";
    }
}

2. Use XmlDocument as told:

public class CClub
{
    int m_id;
    string m_name;

    public void ReadXml(XmlElement element)
    {
        m_id = Convert.ToInt32(element.GetAttribute("Club"));

        foreach (XmlNode node in element.ChildNodes)
        {
            if (node.NodeType == XmlNodeType.Element &&
                node.Name == "Club")
            {
                m_name = node.InnerText;
            }
        }
    }

    public void WriteXml(XmlNode parentNode)
    {
        XmlElement element = parentNode.OwnerDocument.CreateElement("Club");
        parentNode.AppendChild(element);

        // Save the ID
        element.SetAttribute("Club", m_id.ToString());

        // Save the name
        XmlElement elementName = parentNode.OwnerDocument.CreateElement("Name");
        element.AppendChild(elementName);
        elementName.InnerText = m_name;
    }
}

The departement class should look like this:

public class CDepartment
{
    CDepartmentInfo m_departmentInfo;
    CClubs          m_clubs;
    CTeachers       m_teachers;

    public void ReadXml(XmlDocument element)
    {
        foreach (XmlNode node in element.ChildNodes)
        {
            if (node.NodeType == XmlNodeType.Element)
            {
                switch (node.Name)
                {
                    case "DepartmentInfo":
                        m_departmentInfo = new CDepartmentInfo();
                        m_departmentInfo.ReadXml(node as XmlElement);
                    case "Clubs":
                        m_clubs = new CClubs();
                        m_clubs.ReadXml(node as XmlElement);
                    case "Teachers":
                        m_teachers = new CTeachers();
                        m_teachers.ReadXml(node as XmlElement);
                }
            }
        }
    }

    public void WriteXml(XmlDocument document)
    {
        m_departmentInfo.WriteXml(document);
        m_clubs.WriteXml(document);
        m_teachers.WriteXml(document);
    }
}

modified on Saturday, November 29, 2008 4:22 PM

Cool, solution, thanks darkzangel!

regards,
George