C# Discussion Boards - CodeProject

Re: Rich Text Box printing

6-Jul-05 4:00

A simple search on MSDN revealed How To Print the Content of a RichTextBox Control By Using Visual C# .NET[^].

RageInTheMachine9532
"...a pungent, ghastly, stinky piece of cheese!" -- The Roaming Gnome

Taneth6-Jul-05 17:26

Taneth

6-Jul-05 17:26

That actually worked suprisingly well. Thanks.

Propertygrid

Piovra_6-Jul-05 3:00

Piovra_

6-Jul-05 3:00

Is there a way to make a property in a propertygrid which opens up a form (sort of like browsing for an image), when a value is chosen from the form and the form closes i then get the chosen value in the property grid ?

Re: Propertygrid

LongRange.Shooter6-Jul-05 9:42

LongRange.Shooter

6-Jul-05 9:42

Yes.

Check out this article and the associated article:

http://msdn.microsoft.com/library/default.asp?url=/library/en-us/dndotnet/html/usingpropgrid.asp[^]

There are 10 kinds of people in the world.

Those that read binary...

...and those who don't.

DataTable.............

just4ulove76-Jul-05 2:45

6-Jul-05 2:45

Hi,
I am new to Asp.net, I am using the below code on a link-click event to add a row in a datatable and then bind it to a datagrid. But only the last row is visible in the datatable. May be bcoz I am creating a new table on the click. How to get all the values persist on postback???

My code is :

DataTable dt = new DataTable("Requirements");

DataColumn dc= dt.Columns.Add("RequirementId");
DataColumn dc1= dt.Columns.Add("RequirementName");
DataRow row=dt.NewRow();
row["RequirementId"] = "R0001";
row["RequirementName"] = "New Requirement";
dt.Rows.Add(row);

Thanks
dgRequirements.DataSource = new DataView(dt);
dgRequirements.DataBind();

MoustafaS6-Jul-05 3:21

MoustafaS

6-Jul-05 3:21

Set the datagrid's EnableViewState property to true,and then in the second postback ,access it using :

ViewState["Your DataGrid name"]

And then add the last row only to it.

OR

Create a DataTable object at the class level ,and add its value to the viewstate by the same way,and in the click event just :

DataRow row = myDataTable.NewRow();
row["RequirementId"] = "R0001";
row["RequirementName"] = "New Requirement";
myDataTable.Rows.Add(row);

just4ulove76-Jul-05 3:36

6-Jul-05 3:36

hi...
Thx for the reply.

I defined DataTable object at class level.
then I put the below code in form-load
dt=new DataTable();
DataColumn dc= dt.Columns.Add("RequirementId");
DataColumn dc1= dt.Columns.Add("RequirementName");
dgRequirements.DataSource = new DataView(dt); /// datasource to grid

dgRequirements.DataBind();
ViewState["dt"]=dt;

And the Following code at link-click
dt=(DataTable)ViewState["dt"];
DataRow row=dt.NewRow();
row["RequirementId"] = r.RequirementId;
row["RequirementName"] = r.Description;
dt.Rows.Add(row);
ViewState["dt"]=dt;

But its not adding any row in the Datagrid...Whats wrong in the above code?

Thanks a lot.

MoustafaS6-Jul-05 4:47

MoustafaS

6-Jul-05 4:47

You must check first if its a postback or not,
This may work :

Page_load()
{
   if(!IsPostBack)
   {
      //Do your code here.
      dt=new DataTable();
      DataColumn dc= dt.Columns.Add("RequirementId");
      DataColumn dc1= dt.Columns.Add("RequirementName");
   }
   else{
      DataRow row=dt.NewRow();
      row["RequirementId"] = r.RequirementId;
      row["RequirementName"] = r.Description;
      DataTable t = (DataTable)ViewState["dt"];
      t.Rows.Add(row);
      ViewState["dt"] = t;

   }

}

just4ulove76-Jul-05 4:55

How to do this kind of Validation?

6-Jul-05 4:55

Thanks a lot

just4ulove76-Jul-05 2:40

Select all check box in column header

6-Jul-05 2:40

Hi,
I am having various controls say... Estimated Start Date, Estimated End Date(both are text fields with date)

How can I perform these validations using Asp.net Validation Controls
1) If I input Estimated End Date, it is compulsory for me to input Estimated Start Date, other wise it can be left empty.
2) Estimated Start Date >= Todays date (if i input it)

Please Help me..
Thanks

nlecren6-Jul-05 2:33

nlecren

6-Jul-05 2:33

Does anyone know how to create select all capabilities in a listview without using a right click menu or button? What i want is what you see on the web all the time. A little checkbox next to the text in the column header. I don't mind writing a new column header control but to have to create a completely owner drawn listview? That seems crazy.

Thanks

RichTextBox and rtf header/footer

mr_seus6-Jul-05 2:09

mr_seus

6-Jul-05 2:09

I'm developing a small text editor in c# that must have header and footer. The problem is when i load a rtf file with header and footer, they don't appear in the richtextbox. I tryed to change the margins, tryed to set a header footer with richtextbox.rtf = ... Does anyone knows the solution for this?

Re: RichTextBox and rtf header/footer

Dave Kreskowiak6-Jul-05 3:53

Re: RichTextBox and rtf header/footer

6-Jul-05 3:53

AFAIK, the RichTextBox class doesn't support headers and footers.

RageInTheMachine9532
"...a pungent, ghastly, stinky piece of cheese!" -- The Roaming Gnome

mr_seus6-Jul-05 4:16

mr_seus

6-Jul-05 4:16

AFAIK, thank's for reply me. About the richtextbox, i'm extendig the class to support a few features like tables, copy, paste, formating, print, etc... all this using windows api. There's no other solution to the solve problem?

Re: RichTextBox and rtf header/footer

Dave Kreskowiak6-Jul-05 5:22

6-Jul-05 5:22

Other than adding support for it yourself, not that I know of.

RageInTheMachine9532
"...a pungent, ghastly, stinky piece of cheese!" -- The Roaming Gnome

Application.Run question

1nsp1r3d6-Jul-05 0:11

1nsp1r3d

6-Jul-05 0:11

Hi all,

I've a question about Application.Run, which is supposed to start the main loop for receiving messages for windows.forms applications. What I want to do is hide the form on startup, which I do either with setting the Visibility property to false or calling Hide(); so far no problems with that. But when I start the loop with Application.Run(form); it makes the form visible. The thing is that it makes the form visible after calling the constructor so what's the proper way of starting a form with Application.Run(Form); which will be hidden? Any advice is appreaciated Wink | ;)

Regards

MoustafaS6-Jul-05 3:27

MoustafaS

6-Jul-05 3:27

In this form Load event just call :
Hide();.

Dave Kreskowiak6-Jul-05 3:47

6-Jul-05 3:47

That doesn't work.

RageInTheMachine9532
"...a pungent, ghastly, stinky piece of cheese!" -- The Roaming Gnome

occcy6-Jul-05 3:36

occcy

6-Jul-05 3:36

<br />
 private void Form1_Activated(object sender, System.EventArgs e)<br />
 {<br />
   this.Visible=false;<br />
 }<br />

Dave Kreskowiak6-Jul-05 3:39

6-Jul-05 3:39

Now I remember how I did it. It helps to go back and actually look at the damn code!

Override OnLoad and set the form's Opacity to 0. When you need to show the form, reset the Opacity to 1.

RageInTheMachine9532
"...a pungent, ghastly, stinky piece of cheese!" -- The Roaming Gnome